To offset miscellaneous costs, a dealership decides to

This topic has expert replies
User avatar
Master | Next Rank: 500 Posts
Posts: 421
Joined: Sun Apr 17, 2011 4:27 am
Location: India
Thanked: 6 times
Followed by:2 members
GMAT Score:620

Timer

00:00

Your Answer

A

B

C

D

E

Global Stats

To offset miscellaneous costs, a dealership decides to increase the prices of all of its motorcycles by 7 percent plus an additional $350. One motorcycle incurs a 9 percent increase in price because of these changes. What was the original price of this motorcycle?

(A) $15,000
(B) $16,300
(C) $16,500
(D) $17,500
(E) $18,500

OA is D

The wording of this question seems ambiguous
Here's a solution from the Book(veritas):-

Here we apply a percent increase plus a surcharge to yield a larger percent increase. If the original price is our unknown x, we can describe the relationship as 1.07x + 350 = 1.09x. Algebra demands that we subtract 1.07x from both sides, yielding $350 = .02x. Multiply both sides by 50 to get x = $17500, or D.

In my opinion, the highlighted part above doesn't match the given question.

Dealership decides to increase the prices of all of its motorcycles by 7 percent + additional $350.

So, let the price of all of its motorcycles = x
So, after increase = 1.07x + 350

Now, One motorcycle incurs a 9 percent increase in price. What was the original price of this motorcycle?

Let the price of this one motorcycle be y which is increased by 9 percent = 1.09y
I need to find y
My equation becomes --> 1.07x + 350 = 1,09y

I think the wording of the question is ambiguous. Price of all its motorcycles v/s Price of this one motorcycle.
How can there be one variable X for both the above (All V/s This One)

Thanks

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 16207
Joined: Mon Dec 08, 2008 6:26 pm
Location: Vancouver, BC
Thanked: 5254 times
Followed by:1268 members
GMAT Score:770

by Brent@GMATPrepNow » Thu May 17, 2018 9:32 am
vinni.k wrote:To offset miscellaneous costs, a dealership decides to increase the prices of all of its motorcycles by 7 percent plus an additional $350. One motorcycle incurs a 9 percent increase in price because of these changes. What was the original price of this motorcycle?

(A) $15,000
(B) $16,300
(C) $16,500
(D) $17,500
(E) $18,500

OA is D

The wording of this question seems ambiguous
Here's a solution from the Book(veritas):-

Here we apply a percent increase plus a surcharge to yield a larger percent increase. If the original price is our unknown x, we can describe the relationship as 1.07x + 350 = 1.09x. Algebra demands that we subtract 1.07x from both sides, yielding $350 = .02x. Multiply both sides by 50 to get x = $17500, or D.

In my opinion, the highlighted part above doesn't match the given question.

Dealership decides to increase the prices of all of its motorcycles by 7 percent + additional $350.

So, let the price of all of its motorcycles = x
So, after increase = 1.07x + 350

Now, One motorcycle incurs a 9 percent increase in price. What was the original price of this motorcycle?

Let the price of this one motorcycle be y which is increased by 9 percent = 1.09y
I need to find y
My equation becomes --> 1.07x + 350 = 1,09y

I think the wording of the question is ambiguous. Price of all its motorcycles v/s Price of this one motorcycle.
How can there be one variable X for both the above (All V/s This One)

Thanks
I'm not entirely sure this question is ambiguous.
I read it as: one of the motorcycles (we'll name it Clark) gets a 7% price increase PLUS an additional increase of $350
These changes are equivalent to a 9% price increase (for Clark)

As we can see, it doesn't make a difference whether each motorcycle has the same original price. What matters is that increasing a price by 7% and then adding $350 to the price is EQUIVALENT to increasing the price by 9%

So, if c = the original price of Clark, then the NEW PRICE = 1.07c + 350
Likewise. if c = the original price of Clark, then a 9% price increase means the NEW PRICE = 1.09c

So, we can write: 1.07c + 350 = 1.09c

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
Image

User avatar
Master | Next Rank: 500 Posts
Posts: 421
Joined: Sun Apr 17, 2011 4:27 am
Location: India
Thanked: 6 times
Followed by:2 members
GMAT Score:620

by vinni.k » Thu May 17, 2018 11:25 am
Brent@GMATPrepNow wrote:
I'm not entirely sure this question is ambiguous.
I read it as: one of the motorcycles (we'll name it Clark) gets a 7% price increase PLUS an additional increase of $350
These changes are equivalent to a 9% price increase (for Clark)

As we can see, it doesn't make a difference whether each motorcycle has the same original price. What matters is that increasing a price by 7% and then adding $350 to the price is EQUIVALENT to increasing the price by 9%

So, if c = the original price of Clark, then the NEW PRICE = 1.07c + 350
Likewise. if c = the original price of Clark, then a 9% price increase means the NEW PRICE = 1.09c

So, we can write: 1.07c + 350 = 1.09c

Cheers,
Brent
Thanks Brent,

Suppose there are three motorcyles Aye, Bee, and Clark
The price of all of these motorcycles increases by 7 percent.
Now this motorcycle Clark which can be denoted as c, increases by 9% because it's price was increased by 7% when the price of all motorcyles were increased.
I hope i am understanding you clearly.
As Clark is a part of Aye, and Bee. So, we are increasing the price of Clark too, thereby equivalent to 9%

Let me know if i am good on this doubt now.

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 16207
Joined: Mon Dec 08, 2008 6:26 pm
Location: Vancouver, BC
Thanked: 5254 times
Followed by:1268 members
GMAT Score:770

by Brent@GMATPrepNow » Fri May 18, 2018 8:52 am
vinni.k wrote:
Brent@GMATPrepNow wrote:
I'm not entirely sure this question is ambiguous.
I read it as: one of the motorcycles (we'll name it Clark) gets a 7% price increase PLUS an additional increase of $350
These changes are equivalent to a 9% price increase (for Clark)

As we can see, it doesn't make a difference whether each motorcycle has the same original price. What matters is that increasing a price by 7% and then adding $350 to the price is EQUIVALENT to increasing the price by 9%

So, if c = the original price of Clark, then the NEW PRICE = 1.07c + 350
Likewise. if c = the original price of Clark, then a 9% price increase means the NEW PRICE = 1.09c

So, we can write: 1.07c + 350 = 1.09c

Cheers,
Brent
Thanks Brent,

Suppose there are three motorcyles Aye, Bee, and Clark
The price of all of these motorcycles increases by 7 percent.
Now this motorcycle Clark which can be denoted as c, increases by 9% because it's price was increased by 7% when the price of all motorcyles were increased.
I hope i am understanding you clearly.
As Clark is a part of Aye, and Bee. So, we are increasing the price of Clark too, thereby equivalent to 9%

Let me know if i am good on this doubt now.
Sorry, vinni.k, but I don't understand what you are saying. Can you elaborate?

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
Image

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 7262
Joined: Sat Apr 25, 2015 10:56 am
Location: Los Angeles, CA
Thanked: 43 times
Followed by:29 members

by Scott@TargetTestPrep » Tue May 29, 2018 6:44 am
vinni.k wrote:To offset miscellaneous costs, a dealership decides to increase the prices of all of its motorcycles by 7 percent plus an additional $350. One motorcycle incurs a 9 percent increase in price because of these changes. What was the original price of this motorcycle?

(A) $15,000
(B) $16,300
(C) $16,500
(D) $17,500
(E) $18,500
We can let n = the original cost and create the equation:

1.07n + 350 = 1.09n

350 = 0.02n

17,500 = n

Answer: D

Scott Woodbury-Stewart
Founder and CEO
[email protected]

Image

See why Target Test Prep is rated 5 out of 5 stars on BEAT the GMAT. Read our reviews

ImageImage