[GMAT math practice question]
How many possible 7-digit codes can be formed from the letters s, u, c, c, e, s, s?
A. 400
B. 420
C. 450
D. 500
E. 510
How many possible 7-digit codes can be formed from the lette
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- Max@Math Revolution
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When we want to arrange a group of items in which some of the items are identical, we can use something called the MISSISSIPPI rule. It goes like this:Max@Math Revolution wrote:[GMAT math practice question]
How many possible 7-digit codes can be formed from the letters s, u, c, c, e, s, s?
A. 400
B. 420
C. 450
D. 500
E. 510
If there are n objects where A of them are alike, another B of them are alike, another C of them are alike, and so on, then the total number of possible arrangements = n!/[(A!)(B!)(C!)....]
So, for example, we can calculate the number of arrangements of the letters in MISSISSIPPI as follows:
There are 11 letters in total
There are 4 identical I's
There are 4 identical S's
There are 2 identical P's
So, the total number of possible arrangements = 11!/[(4!)(4!)(2!)]
-------NOW ONTO THE QUESTION--------------------
In the word SUCCESS,
There are 7 letters in total
There are 2 identical C's
There are 3 identical S's
So, the total number of possible arrangements = 7!/[(2!)(3!)]
= 420
Answer: B
Cheers,
Brent
- Max@Math Revolution
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=>
The number of permutations of 7 different letters is 7!.
However, 3 of the letters are 's' and 2 of the letters are 'c'. Therefore, the number of permutations of the letters s, u, c, c, e, s, s is 7! / (3! * 2!) = 420.
Therefore, the answer is B.
Answer: B
The number of permutations of 7 different letters is 7!.
However, 3 of the letters are 's' and 2 of the letters are 'c'. Therefore, the number of permutations of the letters s, u, c, c, e, s, s is 7! / (3! * 2!) = 420.
Therefore, the answer is B.
Answer: B
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