Number N is randomly selected from a set of all primes between 10 and 40, inclusive. Number K is selected from a set of all multiples of 5 between 10 and 40 inclusive. What is the probability that N+K is odd?
(A) 1/2
(B) 2/3
(C) 3/4
(D) 4/7
(E) 5/8
Is there a strategic approach to this question? Can any experts help?
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Number N is randomly selected from a set of all primes betwe
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Hello ardz24.
First, you have to notice that N is always an odd number. Then, if you want that N+K is odd, then K has to be even (because N is odd). (it doesn't matter how we select N).
Now, K has to be selected from {10, 15, 20, 25, 30, 35, 40}. (7 options).
So, the favorable cases are k=10, 20, 30, 40. (4 options).
The probability that N+K is odd is equal to:
$$\frac{Favorable\ options}{Total\ options}=\frac{4}{7}.$$
So, the answer should be D.
I hope this can help you.
I'm available if you'd like any follow up.
Regards.
First, you have to notice that N is always an odd number. Then, if you want that N+K is odd, then K has to be even (because N is odd). (it doesn't matter how we select N).
Now, K has to be selected from {10, 15, 20, 25, 30, 35, 40}. (7 options).
So, the favorable cases are k=10, 20, 30, 40. (4 options).
The probability that N+K is odd is equal to:
$$\frac{Favorable\ options}{Total\ options}=\frac{4}{7}.$$
So, the answer should be D.
I hope this can help you.
I'm available if you'd like any follow up.
Regards.
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Notice that there are 2 ways that the sum N+K can be ODDardz24 wrote:Number N is randomly selected from a set of all primes between 10 and 40, inclusive. Number K is selected from a set of all multiples of 5 between 10 and 40 inclusive. What is the probability that N+K is odd?
(A) 1/2
(B) 2/3
(C) 3/4
(D) 4/7
(E) 5/8
1) N is ODD and K is EVEN
2) N is EVEN and K is ODD
However, N cannot be EVEN, since all of the primes between 10 and 40 are ODD (11, 13, 17, 19, . . . . 31, 37)
So, case 2 (above) is impossible
So, P(N+K is odd) = P(N is odd AND K is even)
= P(N is odd) x P(K is even)
------ASIDE-------
Possible values of N: (11, 13, 17, 19, . . . . 31, 37)
So, P(N is odd) = 1
Possible values of K: (10, 15, 20, 25, 30, 35, 40)
So, P(K is even) = 4/7
-----------------------------------------
So, P(N+K is odd) = P(N is odd AND K is even)
= P(N is odd) x P(K is even)
= 1 x 4/7
= 4/7
= D
Cheers,
Brent
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In order for N + K to be odd, we need an even + odd or odd + even.ardz24 wrote:Number N is randomly selected from a set of all primes between 10 and 40, inclusive. Number K is selected from a set of all multiples of 5 between 10 and 40 inclusive. What is the probability that N+K is odd?
(A) 1/2
(B) 2/3
(C) 3/4
(D) 4/7
(E) 5/8
Since N is a prime between 10 and 40, N must be odd.
Thus, we need to determine how many even multiples of 5 there are from 10 to 40 inclusive. We have 10, 20, 30, and 40. We also have (40 - 10)/5 + 1 = 7 total multiples of 5 from 10 to 40 inclusive.
Thus, the probability that N is odd and K is even is 1 x 4/7 = 4/7.
Answer: D
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Hi ardz24,
We're told that number N is randomly selected from a set of all PRIMES between 10 and 40, inclusive and number K is selected from a set of all multiples of 5 between 10 and 40 inclusive. We're asked for the probability that N+K is ODD. For the SUM to be ODD, one of the numbers must be EVEN and the other must be ODD. Since all of the primes from 10 to 40 are ODD, K MUST be EVEN... sowe're ultimately asked for the probability that K is EVEN...
Multiples of 5 from 10 and 40: 10, 15, 20, 25, 30, 35, 40 ---7 numbers
Even numbers in this set: 10, 20, 30, 40 -- 4 numbers
The probability that K is EVEN (and thus, N+K is ODD) = 4/7
Final Answer: D
GMAT assassins aren't born, they're made,
Rich
We're told that number N is randomly selected from a set of all PRIMES between 10 and 40, inclusive and number K is selected from a set of all multiples of 5 between 10 and 40 inclusive. We're asked for the probability that N+K is ODD. For the SUM to be ODD, one of the numbers must be EVEN and the other must be ODD. Since all of the primes from 10 to 40 are ODD, K MUST be EVEN... sowe're ultimately asked for the probability that K is EVEN...
Multiples of 5 from 10 and 40: 10, 15, 20, 25, 30, 35, 40 ---7 numbers
Even numbers in this set: 10, 20, 30, 40 -- 4 numbers
The probability that K is EVEN (and thus, N+K is ODD) = 4/7
Final Answer: D
GMAT assassins aren't born, they're made,
Rich
