What is the best way to solve this absolute value DS problem

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What is the value of y?

(1) 3|x2 – 4| = y – 2

(2) |3 – y| = 11






[spoiler]Answer: C[/spoiler]

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by bourne159 » Wed Sep 03, 2008 11:43 am
Choice 1 is not clear from your post.
But nevertheless since we need to solve for y and there is another variable x choice 1 is not sufficient.

Choice 2
|3 - y| = 11 has two equations

3-y = 11 and
3 -y = -11
This gives two values for y -8 and 14
Hence 2 is not sufficient either

Together they are not sufficient either.
So answer is E.

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by hengirl03 » Wed Sep 03, 2008 11:50 am
Sorry for not writing it clearly.

Choice 1 should be this: (1) 3|x^2 – 4| = y – 2

So from choice (1), you can tell that y>2. Since 3|x^2 – 4| must be positive.


So if you combine what this with what you wrote for (2), you get C.


Thanks for your help!

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by pepeprepa » Wed Sep 03, 2008 12:29 pm
There is no special way for this question.
As Bourne told there is nothing to do with statement 1 alone given there is x and nothing simplifies.
Statement 2
Result is either -8 or 11

With statement 1 and 2 you need to chose a positive one number so it's 11