The measures of the interior angles in a polygon are consecutive integers. The largest angle measures 110 degrees. How many sides does this polygon have?
A) 5
B) 6
C) 7
D) 9
E) 11
OA A
The measures of the interior angles in a polygon
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110 + 110-x + 110-2x + 110-3x + 110-4x = 540The measures of the interior angles in a polygon are consecutive integers. The largest angle measures 110 degrees. How many sides does this polygon have?
550 - 10x = 540
x = 1 ...(1)
Now put the value of x
110 + 109 + 108 + 107 + 106 = 540.
Option (A) is the correct answer.
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how did you derive the above equation . Could you please elaborate ?rintoo22 wrote:110 + 110-x + 110-2x + 110-3x + 110-4x = 540The measures of the interior angles in a polygon are consecutive integers. The largest angle measures 110 degrees. How many sides does this polygon have?
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sum of interior angles = n-2 * 180
lets start with options given.
Lets start with Option A. If polygon has 5 sides, sum of interior angles = 3 * 180 = 540
now given that all angles are consequitive integers, Let those angles be x-2, x-1, x, x+1 and x+2
sum of above (x - 2 + x - 1 + x + x + 1 + x + 2)= 5x = 540
x = 108 degrees
If x = 108, x-2 = 106, x-1 = 107, x+1 = 109 and x+2 (largest) = 110
hence A is our solution.
lets start with options given.
Lets start with Option A. If polygon has 5 sides, sum of interior angles = 3 * 180 = 540
now given that all angles are consequitive integers, Let those angles be x-2, x-1, x, x+1 and x+2
sum of above (x - 2 + x - 1 + x + x + 1 + x + 2)= 5x = 540
x = 108 degrees
If x = 108, x-2 = 106, x-1 = 107, x+1 = 109 and x+2 (largest) = 110
hence A is our solution.
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Important points in the questionhow did you derive the above equation . Could you please elaborate ?
1. Largest angle measures 110
2. Interior angles in a polygon are consecutive integers.
Let x be the difference in consequitive integers (angles)
110 + (110-x) + (110-2x) + (110-3x) + (110-4x).....
Lets plug this equation in the (A) option, 5 sides.
If polygon has 5 sides, sum of interior angles = 3 * 180 = 540.
So 5 angles
110 + (110-x) + (110-2x) + (110-3x) + (110-4x) = 540
we get x = 1
Now put the value of x
110 + 109 + 108 + 107 + 106 = 540.
Hope this helps
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Plugging answer choices is a good strategy for this problem.guerrero wrote:The measures of the interior angles in a polygon are consecutive integers. The largest angle measures 110 degrees. How many sides does this polygon have?
As that has been discussed, I'll post another two methods to solve this problem.
Tricky Approach:
If a polygon has n sides, the sum of the interior angles of the polygon = (n - 2)*180°
Hence, the sum must be a multiple of 10, i.e. units digit of the sum must be 0.
As the largest angle measures 110° and the angles are consecutive integers, the next angles will be 109°, 108°, ... etc
The 1st time we get zero as units digit when we start adding the units place of these measures is (0 + 9 + 8 + 7 + 6) ---> Hence, 5 angles --> n = 5
The 2nd time we get zero as units digit when we start adding the units place of these measures is (0 + 9 + 8 + 7 + 6 + 5 + 4 + 3 + 2 + 1 + 0 + ...) ---> Hence, more than 11 angles angles --> n > 11
Hence, the polygon has 5 sides.
The correct answer is A.
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Algebraic Approach:
Say, the number of sides of the polygon is n.
Hence, sum of the interior angles of the polygon = (n - 2)*180°
Largest angle is 110° and all the interior angles are consecutive integers.
Hence, the measures of the interior angles of the polygon in degrees are 110, (110 - 1), (110 - 2), ..., and (110 - (n - 1)).
So, sum of the angles = [110 + (110 - 1) + (110 - 2) + ... + (110 - (n - 1))]
= (110 + 110 + ... n times) - (1 + 2 + ... + (n - 1))
= 110n - sum of first (n - 1) integers
= 110n - n(n - 1)/2
So, 110n - n(n - 1)/2 = (n - 2)*180
--> 220n - n² + n = 360n - 720
--> n² + 139n - 720 = 0
--> n² - 5n + 144n - 720 = 0
--> (n - 5)(n + 144) = 0
As n cannot be negative, only possible value of n is 5.
The correct answer is A.
Say, the number of sides of the polygon is n.
Hence, sum of the interior angles of the polygon = (n - 2)*180°
Largest angle is 110° and all the interior angles are consecutive integers.
Hence, the measures of the interior angles of the polygon in degrees are 110, (110 - 1), (110 - 2), ..., and (110 - (n - 1)).
So, sum of the angles = [110 + (110 - 1) + (110 - 2) + ... + (110 - (n - 1))]
= (110 + 110 + ... n times) - (1 + 2 + ... + (n - 1))
= 110n - sum of first (n - 1) integers
= 110n - n(n - 1)/2
So, 110n - n(n - 1)/2 = (n - 2)*180
--> 220n - n² + n = 360n - 720
--> n² + 139n - 720 = 0
--> n² - 5n + 144n - 720 = 0
--> (n - 5)(n + 144) = 0
As n cannot be negative, only possible value of n is 5.
The correct answer is A.
Anju Agarwal
Quant Expert, Gurome
Backup Methods : General guide on plugging, estimation etc.
Wavy Curve Method : Solving complex inequalities in a matter of seconds.
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Quant Expert, Gurome
Backup Methods : General guide on plugging, estimation etc.
Wavy Curve Method : Solving complex inequalities in a matter of seconds.
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