What is the remainder when the positive integer x is divided by 6?
(1) When x is divided by 2, the remainder is 1; and when x is divided by 3 the remainder is zero
(2) When x is divided by 12, the remainder is 3.
Can someone put some light to this question.
Thanks..
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pepeprepa
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Each one is sufficient --> D (not C I confused letters)
I do not frame the problem I just take examples
With 1) are possible 3, 9, 15, 21 .... and their remainder is 3 when divided by 6
With 2) Divided by 12 remainder is 3.... we have 3, 15, 27 and their remainder is 3 when divided by 6
I do not frame the problem I just take examples
With 1) are possible 3, 9, 15, 21 .... and their remainder is 3 when divided by 6
With 2) Divided by 12 remainder is 3.... we have 3, 15, 27 and their remainder is 3 when divided by 6
Last edited by pepeprepa on Fri Jul 25, 2008 6:36 am, edited 2 times in total.
With option 1 : 3, 9, 15, 21 ...
I have doubt here - since 3 is smaller than 6 , I am not sure if it can be considered as - 6x0 + 3. Any inputs ?
I think option two is sufficient to answer the question :
Remainder is 3 when divided by 12 , so number can be --- 15, 27, 39, 51 ...
In all the scenarios if the no. is divided by 6, the remainder is 3.
So, B i think.
I have doubt here - since 3 is smaller than 6 , I am not sure if it can be considered as - 6x0 + 3. Any inputs ?
I think option two is sufficient to answer the question :
Remainder is 3 when divided by 12 , so number can be --- 15, 27, 39, 51 ...
In all the scenarios if the no. is divided by 6, the remainder is 3.
So, B i think.
Last edited by apnamit on Fri Jul 25, 2008 6:27 am, edited 1 time in total.
how does 3/6 give you a remainder of 3....not quite sure of that ....can you please put in a little input for me please.... Thanks... and how does 1/2 give you a remainder of 1....
I AM TOTALLY CONFUSED>......
I AM TOTALLY CONFUSED>......
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pepeprepa
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Read it first, the link is good.
I quote some lines.
pepeprepa wrote:
I know that now: "Every n divided by k with n<k has a remainder of n"
That's almost true- it's definitely true if n is greater than or equal to zero, and less than k. If n can be negative, then the above is not true.
I quote some lines.
pepeprepa wrote:
I know that now: "Every n divided by k with n<k has a remainder of n"
That's almost true- it's definitely true if n is greater than or equal to zero, and less than k. If n can be negative, then the above is not true.
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Ian Stewart
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The question asked above is "What is the remainder when 3 is divided by 6?"
First, how do we find remainders? If I ask, what is the remainder when 13 is divided by 6, I think we can all agree the answer is 1. To find the remainder here, we find the nearest multiple of 6 that is smaller than 13 -- which is 12 -- and then work out how much larger 13 is: 13 -12 = 1. We do the same when we divide 3 by 6; the nearest multiple of 6 that is smaller than 3 is zero (because 6*0 = 0), and 3 - 0 = 3, so the remainder is 3.
Hope that clears things up a bit!
First, how do we find remainders? If I ask, what is the remainder when 13 is divided by 6, I think we can all agree the answer is 1. To find the remainder here, we find the nearest multiple of 6 that is smaller than 13 -- which is 12 -- and then work out how much larger 13 is: 13 -12 = 1. We do the same when we divide 3 by 6; the nearest multiple of 6 that is smaller than 3 is zero (because 6*0 = 0), and 3 - 0 = 3, so the remainder is 3.
Hope that clears things up a bit!
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