In a certain game of dice, the player's score is determined as a sum of three throws of a single die. The player with the highest score wins the round. If more than one player has the highest score, the winnings of the round are divided equally among these players. If Jim plays this game against 21 other players, what is the probability of the minimum score that will guarantee Jim some monetary payoff?
a. 41/50
b. 1/221
c. 1/216
d. 1/84
e. 1/42
OA: C
Probability
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The language of the question is confusing, but all is asking for P(of getting 3 6's) as this will make sure that Jim gets some monetary payoff.
P(of getting 3 6's) = 1/6*1/6*1/6 = [spoiler]1/216[/spoiler].
Hope this makes sense!!!
P(of getting 3 6's) = 1/6*1/6*1/6 = [spoiler]1/216[/spoiler].
Hope this makes sense!!!
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