A 4 cm cube is cut into 1 cm cubes. What is the percentage increase in the surface area after such cutting?
* 4%
* 166%
* 266%
* 300%
* 400%
PS Percentage problem
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- simplyjat
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Surface area of the cube = 6*Side*Side
Initial surface area of one cube = 6 * 4 * 4 = 96
New surface are of 64 cubes = 64 * 6 * 1 * 1 = 384
%increase = (384 - 96)/96 = 320 / 96 = 333.33 %
Did you miss something in the question...
Initial surface area of one cube = 6 * 4 * 4 = 96
New surface are of 64 cubes = 64 * 6 * 1 * 1 = 384
%increase = (384 - 96)/96 = 320 / 96 = 333.33 %
Did you miss something in the question...
simplyjat
simplyjat, you were exactly right, except (384 - 96)/96 = 288 / 96 = 300% increase.simplyjat wrote:Surface area of the cube = 6*Side*Side
Initial surface area of one cube = 6 * 4 * 4 = 96
New surface are of 64 cubes = 64 * 6 * 1 * 1 = 384
%increase = (384 - 96)/96 = 320 / 96 = 333.33 %
Did you miss something in the question...
- simplyjat
- Master | Next Rank: 500 Posts
- Posts: 423
- Joined: Thu Dec 27, 2007 1:29 am
- Location: Hyderabad, India
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- Followed by:2 members
- GMAT Score:770
Silly mistakes...tmmyc wrote:simplyjat, you were exactly right, except (384 - 96)/96 = 288 / 96 = 300% increase.simplyjat wrote:Surface area of the cube = 6*Side*Side
Initial surface area of one cube = 6 * 4 * 4 = 96
New surface are of 64 cubes = 64 * 6 * 1 * 1 = 384
%increase = (384 - 96)/96 = 320 / 96 = 333.33 %
Did you miss something in the question...
simplyjat