GMAT Prep Help!!!

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GMAT Prep Help!!!

by nimish_rulz » Thu Apr 03, 2008 6:33 pm
Hi I have 4 problems from one of my GmatPrep Test can some1 please explain how to solve these?

I am attaching all four problems in 1 document
Attachments
Q1.JPG
Q2.JPG
Q3.JPG
Q4.JPG
Past is: Behind Me---Future is: Secure---Present is: An Aim To Crack The GMAT. So I say lets do it!

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by Neo2000 » Thu Apr 03, 2008 10:47 pm
Next time, please post the questions in the thread itself. Makes it easier for all to answer.

Q1. At the very least n has to be 30 or multiples thereof. Prime factors of 30 are 2,3 and 5

Thus 3 different factors.

Q2. The problem states
1X +2Y +3Z = 1.5(X+Y+Z)
Simplify this to get your answer

For Q3 Consider positive numbers 1 and 2 and substitute. Only option E suffices. Think Commutative Property.

For Q4, 1Equation 2 Unknowns means neither statement will suffice. That immediately eliminates options A,B, D . You are left with either C or E.

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by nimish_rulz » Fri Apr 04, 2008 8:06 am
Thanks NEO :D
Past is: Behind Me---Future is: Secure---Present is: An Aim To Crack The GMAT. So I say lets do it!

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by preciousrain7 » Mon Apr 14, 2008 2:18 pm
Neo2000 wrote:Next time, please post the questions in the thread itself. Makes it easier for all to answer.

Q1. At the very least n has to be 30 or multiples thereof. Prime factors of 30 are 2,3 and 5

Thus 3 different factors.

Q2. The problem states
1X +2Y +3Z = 1.5(X+Y+Z)
Simplify this to get your answer

For Q3 Consider positive numbers 1 and 2 and substitute. Only option E suffices. Think Commutative Property.

For Q4, 1Equation 2 Unknowns means neither statement will suffice. That immediately eliminates options A,B, D . You are left with either C or E.
Hi can you plz explain your ans to problem #3? thanks a lot

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by tmmyc » Mon Apr 14, 2008 3:58 pm
preciousrain7 wrote:Hi can you plz explain your ans to problem #3? thanks a lot
For number 3, it states

f(a+b) = f(a) + f(b)

This means if you substitute 'a' for 'x', and then substitute 'b' for 'x', and then add the two together, then it equals substituting 'a+b' for 'x'.

You can see that see that some obviously don't work:
f(x) = x+1
f(a) = a+1
f(b) = b+1
f(a) + f(b) = a+1+b+1 = a+b+2

f(a+b) = a+b+1

Some are less obvious
f(x) = x^2
f(a) = a^2
f(b) = b^2
f(a) + f(b) = a^2 + b^2

f(a+b) = (a+b)^2 = a^2 + 2ab + b^2


And only answer E works
f(x) = -3x
f(a) = -3a
f(b) = -3b
f(a) + f(b) = -3a - 3b

f(a+b) = -3(a+b) = -3a - 3b