Is the number of seconds required to travel d1 feet at
r1 feet per second greater than the number of seconds
required to travel d2 feet at r2 feet per second?
(1) d1 is 30 greater than d2.
(2) r1 is 30 greater than r2.
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cans
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krishnasty
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basically, question is asking , is d1/r1 > d2/r2 ??cans wrote:Is the number of seconds required to travel d1 feet at
r1 feet per second greater than the number of seconds
required to travel d2 feet at r2 feet per second?
(1) d1 is 30 greater than d2.
(2) r1 is 30 greater than r2.
1 ) it means is d1/r1 > (d1-30)/r2 ?
We have no idea wat is r1 or r2 and what is the relation, Hence, insufficient
2) it means is d1/r1 > d2 /(r1-30) ?
again, no idea wat is d1 and d2. hence, insufficient
Combining both,
is d1/r1 > (d1-30)/(r1-30) ?
now, if d1 is greater than r1, then ans is yes. If d1 < r1, then, ans is no.
Hence, insufficent
IMO E
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GMATGuruNY
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Is d1/r1 > d2/r2?cans wrote:Is the number of seconds required to travel d1 feet at
r1 feet per second greater than the number of seconds
required to travel d2 feet at r2 feet per second?
(1) d1 is 30 greater than d2.
(2) r1 is 30 greater than r2.
Look for combinations that satisfy both statements:
Let d2=1, d1=31, r2=1, r1=31.
Is 31/31>1/1? No.
Let d2=1, d1=31, r2=2, r1=32.
Is 31/32>1/2? Yes.
Since the combinations above satisfy both statements, and in the first case the answer is No and in the second case the answer is Yes, insufficient.
The correct answer is E.
Last edited by GMATGuruNY on Wed Jun 08, 2011 5:34 am, edited 1 time in total.
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rveeraga
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In inequalities, distributing to minimum expression helps, especially in data sufficiency.
Combining both statements,
is 30+d2/30+r2 > d2/r2 ? (we know that the variables are positive)
=> is 30r2+d2r2 > 30d2+d2r2 ?
=> is r2 > d2 ?
none of the statements give relation between r2 and d2. So, insufficient. E.
Combining both statements,
is 30+d2/30+r2 > d2/r2 ? (we know that the variables are positive)
=> is 30r2+d2r2 > 30d2+d2r2 ?
=> is r2 > d2 ?
none of the statements give relation between r2 and d2. So, insufficient. E.
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cans
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OA E
If my post helped you- let me know by pushing the thanks button
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