Data Sufficiency

In the fraction x/y, where x and y are positive integers, what i sthe value of y?

1) The least common denominator of x/y and 1/3 is 6.
2) x = 1

This question is really confusing, "least common denominator" is not HCF or LCM...Least common denominator of anything should be 1...

Calista are you sure you copied that correctly??

Least Common denominator is usually applied to fractions. We unknowingly do L.C.D all the time when adding fractions

From the Q..

1. x/y + 1/3 has L.C.D. of 6 .
i.e. L.C.M (y,3) = 6 which gives y =2 (if the fraction is in reduced form)

But, x/y can be 2/4, which makes y =4..

So Not SUFF


2. x= 1, no way to find y.


Combining 1 & 2, y =2
SUFF

ANS: C

let me know if it matches with OA.

we do the Least Common Multiple when adding fractions....

Correct me if i am wrong.

L.C.M (y,3) = 6 which gives y =2 (if the fraction is in reduced form)

This interpolation is incorrect y can be 6 as well...

You are right.. Its a possibility..

So combining 1 & 2, y can be either 2 or 6.

So it should be E.

Looks like i need to spend few seconds extra before i conclude

Thx for catching!

Yeah I too was confused with the question. But the question is correct and I think malnv's solution is good.

So rephrasing is LCD just LCM of denomitors?

Calista.

E is the correct answer for the question...
Thanks for updating the solution malnv