If X is not equal to 0. Then √(x^2)/x = ?
A. -1
B. 0
C. 1
D. x
E. IxI / x
Ans: [spoiler]E[/spoiler]
Please correct me If i'm wrong.
I got the answer C.
I took √(x^2)/x = |x|/x = x/x= 1
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this question is posted...sindhujah_kk wrote:If X is not equal to 0. Then √(x^2)/x = ?
A. -1
B. 0
C. 1
D. x
E. IxI / x
Ans: E
Please correct me If i'm wrong.
I got the answer C.
I took √(x^2)/x = |x|/x = x/x= 1
ok, if the squroot of a numbers : 9, 4 , it will be 3, 4
i meant V(9)^2=3
but if Vx^2=|x| and |x|= +,- x
so if x>0 so the answer will be 1 , C
if x<0 the answer will be -1 because |x| when x<0 is still x while x in denominator is -x
thus E makes sense
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Your mistake is the red one.sindhujah_kk wrote:If X is not equal to 0. Then √(x^2)/x = ?
A. -1
B. 0
C. 1
D. x
E. IxI / x
Ans: E
Please correct me If i'm wrong.
I got the answer C.
I took √(x^2)/x = |x|/x = x/x= 1
|x| means the absolute value of x, thus
- (1) |x| = x , if x positive
(2) |x| = -x , if x negative
- = x/x = 1 , if x positive
= -x/x = -1 , if x negative
Rahul Lakhani
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Quant Expert
Gurome, Inc.
https://www.GuroMe.com
On MBA sabbatical (at ISB) for 2011-12 - will stay active as time permits
1-800-566-4043 (USA)
+91-99201 32411 (India)