A certain basketball team that has played 2/3 of its games has a record of 17 wins and 3 losses. What is the greatest number of the remaining games that the team can lose and still win at least 3/4 of all of its games?
(A) 7
(B) 6
(C) 5
(D) 4
(E) 3
ANS: D
problem
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17 wins 3 loses = 20 games =2/3 of total games
so total = 30 games
3/4 of 30 = 22.5 approx so it should be 23 games (atleast 3/4)
so in remaining 10 games it should win 23 -17 =6 games
so max it can loose is 4
so total = 30 games
3/4 of 30 = 22.5 approx so it should be 23 games (atleast 3/4)
so in remaining 10 games it should win 23 -17 =6 games
so max it can loose is 4
Regards
Samir
Samir