Which of the following is a possible length for side AB of triangle ABC if AC = 6 and BC = 9?
I. 3
II. 9
III. 13.5
I only
II only
III only
II and III
I, II and III
qa is c..i chose a
manhatan 4
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In a triangle, sum of two sides should be greater than the third side at any point.
Given sides, AC = 6, BC= 9
Options:
1) 3 (AC+3 = 6+3 = 9 = BC). This is incorrect as the sum of 2 sides is equal to the third side.
options II and III are possible . So i think answer should be (d).
Given sides, AC = 6, BC= 9
Options:
1) 3 (AC+3 = 6+3 = 9 = BC). This is incorrect as the sum of 2 sides is equal to the third side.
options II and III are possible . So i think answer should be (d).
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I agree. The answer should be D.
9-6 = 3 and 6+9 = 15, both of which would end up giving you a straight line, which is not a triangle. In order to keep the triangle, the third side must be 3<AB<15.
9-6 = 3 and 6+9 = 15, both of which would end up giving you a straight line, which is not a triangle. In order to keep the triangle, the third side must be 3<AB<15.
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The shortest distance between any two points is a straight line. Therefore, every side of a triangle has to be LESS than the sum of the other two sides.
In other words, going straight from point A to point B MUST be shorter than going from A to C and then C to B.
For this rule to hold true for all 3 sides of a triangle, every side must also be GREATER than the difference between the other two sides.
So, the general rule is:
|Side 2 - Side 3| < Side 1 < Side 2 + Side 3
and this rule holds true for every side.
In other words, going straight from point A to point B MUST be shorter than going from A to C and then C to B.
For this rule to hold true for all 3 sides of a triangle, every side must also be GREATER than the difference between the other two sides.
So, the general rule is:
|Side 2 - Side 3| < Side 1 < Side 2 + Side 3
and this rule holds true for every side.
Stuart Kovinsky | Kaplan GMAT Faculty | Toronto
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Hi Stuart, I do not understand this. Can you please explain in more detail.Stuart Kovinsky wrote:The shortest distance between any two points is a straight line. Therefore, every side of a triangle has to be LESS than the sum of the other two sides.
In other words, going straight from point A to point B MUST be shorter than going from A to C and then C to B.
For this rule to hold true for all 3 sides of a triangle, every side must also be GREATER than the difference between the other two sides.
So, the general rule is:
|Side 2 - Side 3| < Side 1 < Side 2 + Side 3
and this rule holds true for every side.
Never heard about, or seen this kind of rule anywhere else. And, I could not do it using geometry principles too.
Thanks in advance!
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Sure!bikerguy.gmat wrote:Hi Stuart, I do not understand this. Can you please explain in more detail.Stuart Kovinsky wrote:The shortest distance between any two points is a straight line. Therefore, every side of a triangle has to be LESS than the sum of the other two sides.
In other words, going straight from point A to point B MUST be shorter than going from A to C and then C to B.
For this rule to hold true for all 3 sides of a triangle, every side must also be GREATER than the difference between the other two sides.
So, the general rule is:
|Side 2 - Side 3| < Side 1 < Side 2 + Side 3
and this rule holds true for every side.
Never heard about, or seen this kind of rule anywhere else. And, I could not do it using geometry principles too.
Thanks in advance!
Let's start with two houses, A and B.
Let's build a road in a straight line directly from A to B. That's the shortest possible road that we can build to connect the two houses.
Now let's build a third house, C, and build direct roads from A to C and from C to B.
We now have two possible routes to get from A to B. We can go directly from A to B, or we can go from A to C to B.
Another way we can think of AC and CB is as a detour from points A to B. Since the shortest distance between A and B is our original straight road, we can see that:
AB < AC + CB
Now for the second part of the relationship. What we just determined about AB must also be true for AC and CB. In other words:
AC < AB + CB
and
CB < AB + AC
We simply rearrange these inequalities:
AB < AC + CB
provides:
AB - CB < AC
AB - AC < CB
AC < AB + CB
provides:
AC - AB < CB
AC - CB < AC
CB < AB + AC
provides:
CB - AB < AC
CB - AC < AB
Putting those 9 inequalities together, we get:
|AB - AC| < CB < AB + AC
|AC - CB| < AB < AC + CB
|CB - AB| < AC < CB + AB
Stuart Kovinsky | Kaplan GMAT Faculty | Toronto
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ohh brilliant!!!!
thanks Stuart, your explanation is amazing.
all your posts are really helpful. keep the good work going
Ciao!
-Avinash
thanks Stuart, your explanation is amazing.
all your posts are really helpful. keep the good work going
Ciao!
-Avinash
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Hey guys, it is just the basic rule for triangles' sides.
No side can be longer than the sum of other two sides.
Then you have to solve an inequality and find out what actually can be the side of a triangle. Rule is applicable to triangles of all types.
No side can be longer than the sum of other two sides.
Then you have to solve an inequality and find out what actually can be the side of a triangle. Rule is applicable to triangles of all types.