In the xy-plane, the points (c, d), (c, -d), and (-c, -d) are three vertices of a certain square. If c < 0 and d > 0, which of the following points is in the same quadrant as the fourth vertex of the square?
A. (-5, -3)
B. (-5, 3)
C. (5, -3)
D. (3, -5)
E. (3, 5)
Problem solving
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IMPORTANT: c < 0 and d > 0Newaz111 wrote:In the xy-plane, the points (c, d), (c, -d), and (-c, -d) are three vertices of a certain square. If c < 0 and d > 0, which of the following points is in the same quadrant as the fourth vertex of the square?
A. (-5, -3)
B. (-5, 3)
C. (5, -3)
D. (3, -5)
E. (3, 5)
In other words, c is NEGATIVE and d is POSITIVE
Let's examine each of the three given vertices:
(c, d): So, we get (NEGATIVE, POSITIVE). This vertex is in quadrant II
(c, -d): So, we get (NEGATIVE, -POSITIVE), which simplifies to (NEGATIVE, NEGATIVE). This vertex is in quadrant III
(-c, -d): So, we get (-NEGATIVE, -POSITIVE), which simplifies to (POSITIVE, NEGATIVE). This vertex is in quadrant IV
So, the last vertex must be in quadrant I
Only (3, 5) is in quadrant I
Answer: E
Cheers,
Brent