Hello,
Can you please assist with this:
In the figure above, polygon ABCDEF is equilateral and has perimeter 42. If AB is
parallel to ED, AF is parallel to BC, EF is parallel to CD, and x equals 60
degrees, what is the length of line segment BD (not shown)?
OA: [spoiler]7.sqroot(3)[/spoiler]
To find the length of BD
This topic has expert replies
-
- Legendary Member
- Posts: 641
- Joined: Tue Feb 14, 2012 3:52 pm
- Thanked: 11 times
- Followed by:8 members
GMAT/MBA Expert
- [email protected]
- Elite Legendary Member
- Posts: 10392
- Joined: Sun Jun 23, 2013 6:38 pm
- Location: Palo Alto, CA
- Thanked: 2867 times
- Followed by:511 members
- GMAT Score:800
Hi gmmattesttaker2,
I'm going to give you a couple of hints and let you try this question again:
1) Look for "hidden" right triangles. Notice how x = 60 degrees? Think about WHERE you could find right triangles inside and OUTSIDE of the given shape.
2) Since the 6-sided shape is equilateral, what does that mean about the 6 sides?
3) Line segment BD is OUTSIDE the shape. Try drawing that into the picture, then cut that line IN HALF.
GMAT assassins aren't born, they're made,
Rich
I'm going to give you a couple of hints and let you try this question again:
1) Look for "hidden" right triangles. Notice how x = 60 degrees? Think about WHERE you could find right triangles inside and OUTSIDE of the given shape.
2) Since the 6-sided shape is equilateral, what does that mean about the 6 sides?
3) Line segment BD is OUTSIDE the shape. Try drawing that into the picture, then cut that line IN HALF.
GMAT assassins aren't born, they're made,
Rich
-
- Legendary Member
- Posts: 641
- Joined: Tue Feb 14, 2012 3:52 pm
- Thanked: 11 times
- Followed by:8 members
Hi Rich,[email protected] wrote:Hi gmmattesttaker2,
I'm going to give you a couple of hints and let you try this question again:
1) Look for "hidden" right triangles. Notice how x = 60 degrees? Think about WHERE you could find right triangles inside and OUTSIDE of the given shape.
2) Since the 6-sided shape is equilateral, what does that mean about the 6 sides?
3) Line segment BD is OUTSIDE the shape. Try drawing that into the picture, then cut that line IN HALF.
GMAT assassins aren't born, they're made,
Rich
I was wondering if length BD is also included in the perimeter of ABCDEF and similarly if AE would also be included in the perimeter of ABCDEF?
Thanks,
Sri
- Uva@90
- Master | Next Rank: 500 Posts
- Posts: 490
- Joined: Thu Jul 04, 2013 7:30 am
- Location: Chennai, India
- Thanked: 83 times
- Followed by:5 members
Hi Sri,gmattesttaker2 wrote:Hello,
Can you please assist with this:
In the figure above, polygon ABCDEF is equilateral and has perimeter 42. If AB is
parallel to ED, AF is parallel to BC, EF is parallel to CD, and x equals 60
degrees, what is the length of line segment BD (not shown)?
OA: [spoiler]7.sqroot(3)[/spoiler]
Given: X = 60 Degree and each side of length 7
We need to find Length of BD.
Length of BD = Length of AE.
Draw a line Joining B and E and it Intersects Line FC, lets keep that point as G.
Now AE = AG+GE
Consider triangle AFG.
It forms a 30:60:90 Triangle.
Whose sides will be in the ration x:√3X:2X
we know that side for the angle 90 is 7
hence 2X = 7 => X = 7/2
we need AG which is formed by 60 degree angle,
So AG = (7/2)*√3
Similarly do for another triangle, FGE
you will end up GE = (7/2)*√3
Hence AE = (7/2)*√3+ (7/2)*√3 = 7√3
BD = 7√3
Hope it helps you.
Regards,
Uva.
Known is a drop Unknown is an Ocean
- sanju09
- GMAT Instructor
- Posts: 3650
- Joined: Wed Jan 21, 2009 4:27 am
- Location: India
- Thanked: 267 times
- Followed by:80 members
- GMAT Score:760
Join BD, drop CQ perpendicular on BD, this would create two identical 30-60-90 triangles in which BQ = QD = 3.5√3 by property; hence BD = 7√3.gmattesttaker2 wrote:Hello,
Can you please assist with this:
In the figure above, polygon ABCDEF is equilateral and has perimeter 42. If AB is
parallel to ED, AF is parallel to BC, EF is parallel to CD, and x equals 60
degrees, what is the length of line segment BD (not shown)?
OA: [spoiler]7.sqroot(3)[/spoiler]
The mind is everything. What you think you become. -Lord Buddha
Sanjeev K Saxena
Quantitative Instructor
The Princeton Review - Manya Abroad
Lucknow-226001
www.manyagroup.com
Sanjeev K Saxena
Quantitative Instructor
The Princeton Review - Manya Abroad
Lucknow-226001
www.manyagroup.com