can somebody please help me with the below problem:
"How many 5 letter initials can be formed using alphabet of the english language that contain 2 distinct vowels and 3 distinct consonants"
permutation /combination problem
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- dumb.doofus
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5c2*21c3 = 13300
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different positions of the vowels/consonants would give rise to different initials. so total number of initials would be
5c2*21c3*5! = 13300*120=1596000
5c2*21c3*5! = 13300*120=1596000