Is 26 < x < 49 ?
1) 30 < x < 52
2) 24 < x < 42
OA C
perceptively easy question
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1) x can be 40 (YES) or 51(NO). Insufficientniraj_a wrote:Is 26 < x < 49 ?
1) 30 < x < 52
2) 24 < x < 42
2) x can be 40 (YES) or 25(NO). Insufficient.
Combining both statements, we are sure that x > 30 and x <42. Therefore 26<x<49 is TRUE. Sufficient. Choose C.
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Looks simple but a very nice question indeed (to refrsesh us on some basic concepts)
Is 26 < x < 49 ?
1) 30 < x < 52
2) 24 < x < 42
Is x > 26 but <49
Stmt I
Sufficient to say 26<x (lower limit)but not x<49
INSUFF as a whole
Stmt II
24 < x < 42
sufficient to say x<49(upper limit) but not 26<x
INSUFF as a whole
Stmt I and II together
We can most defnitely say 26 < x < 49
C)
Is 26 < x < 49 ?
1) 30 < x < 52
2) 24 < x < 42
Is x > 26 but <49
Stmt I
Sufficient to say 26<x (lower limit)but not x<49
INSUFF as a whole
Stmt II
24 < x < 42
sufficient to say x<49(upper limit) but not 26<x
INSUFF as a whole
Stmt I and II together
We can most defnitely say 26 < x < 49
C)
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Is 26 < x < 49 ?
24......30.........42.......52
24......30.........42.......52\
24...26...30.........42...49....52
C
24......30.........42.......52
24......30.........42.......52\
24...26...30.........42...49....52
C
LGTCH
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That's right Niraj. If x is defined to be between 10 and 20, and a further restriction is posed where 13<x<17, then you are sure that x will never be 11, 12, 13, 17, etc.niraj_a wrote:@BM
so in inequalities we take the most restrictive of the high/low ranges?
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