I don't see how to solve a problem like this one:
If x is different from 3, then (3x(x-3) -x +3)/(x-3) = ...
A : X+1
B : X-3
C : 3x +1
D : 3x -1
E : 3X +3
Any help welcome! Thanks!
Just don't see how to get started with this one
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- GMATBeater77
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- GMATBeater77
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Thanks, that's totally correct.
I understand your approach however I wouldn't have come to this solution myself.
Is there some kind of strategy to approach these kind of problems.
I understand your approach however I wouldn't have come to this solution myself.
Is there some kind of strategy to approach these kind of problems.
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The biggest thing is to look for an opportunity to factor out a common term. In this case, the fact that we have (x-3) in the numerator and the denominator should point us in the right direction.GMATBeater77 wrote:Thanks, that's totally correct.
I understand your approach however I wouldn't have come to this solution myself.
Is there some kind of strategy to approach these kind of problems.
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Let x=0.GMATBeater77 wrote:I don't see how to solve a problem like this one:
If x is different from 3, then (3x(x-3) -x +3)/(x-3) = ...
A : X+1
B : X-3
C : 3x +1
D : 3x -1
E : 3X +3
Any help welcome! Thanks!
Then (3x(x-3) -x +3)/(x-3) = (0-0+3)/(0-3) = -1. This is our target.
Now we plug x=0 into the answers to see which yields our target of -1.
Only D works:
3x-1 = 3(0)-1 = -1.
The correct answer is D.
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Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.
As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.
For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
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