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If it takes Jacob x hours to complete a project and it takes Mike y hours to complete the same project, how many hours

Expert replies
by BTGmoderatorDC » Sun Nov 01, 2020 4:55 pm

Timer

00:00

Answers

A

B

C

D

E

Stats

Difficulty—

If it takes Jacob x hours to complete a project and it takes Mike y hours to complete the same project, how many hours will it take them to complete the project if they are working together?

A. xy/(x+y)

B. (x+y)/(xy)

C. x+y

D. xy

E. x–y


OA A

Source: Veritas Prep
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Source: — Problem Solving |

BTGmoderatorDC wrote: ↑
Sun Nov 01, 2020 4:55 pm
If it takes Jacob x hours to complete a project and it takes Mike y hours to complete the same project, how many hours will it take them to complete the project if they are working together?

A. xy/(x+y)

B. (x+y)/(xy)

C. x+y

D. xy

E. x–y


OA A

Source: Veritas Prep
For work questions, there are two useful rules:

Rule #1: If a person can complete an entire job in k hours, then in one hour, the person can complete 1/k of the job
Example: If it takes Sue 5 hours to complete a job, then in one hour, she can complete 1/5 of the job. In other words, her work rate is 1/5 of the job per hour

Rule #2: If a person completes a/b of the job in one hour, then it will take b/a hours to complete the entire job
Example: If Sam can complete 1/8 of the job in one hour, then it will take him 8/1 hours to complete the job.
Likewise, if Joe can complete 2/3 of the job in one hour, then it will take him 3/2 hours to complete the job.

Let’s use these rules to solve the question. . . .

It takes Jacob x hours to complete a project and it takes Mike y hours to complete the same project
So, applying Rule #1....
Jacob completes 1/x of the job in ONE HOUR
Mike completes 1/y of the job in ONE HOUR
So, in ONE HOUR, the two workers complete 1/x + 1/y of the job

1/x + 1/y = y/xy + x/xy
= (x + y)/xy

In other words, in ONE HOUR, the two workers complete (x + y)/xy of the job
Applying Rule #2, the total time to COMPLETE the job = xy/(x + y)

Answer: A

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
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BTGmoderatorDC wrote: ↑
Sun Nov 01, 2020 4:55 pm
If it takes Jacob x hours to complete a project and it takes Mike y hours to complete the same project, how many hours will it take them to complete the project if they are working together?

A. xy/(x+y)

B. (x+y)/(xy)

C. x+y

D. xy

E. x–y


OA A

Solution:

Jacob’s rate is 1/x, and Mike’s rate is 1/y. We can create the following combined rate expression:

1/x + 1/y = y/(xy) + x/(xy) = (x + y)/(xy)

Since time is the inverse of rate, it will take them xy/(x+y) hours to complete the project.

Answer: A

Scott Woodbury-Stewart
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