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## any one feel confident on Geometry?

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### any one feel confident on Geometry?

by sanjib » Thu Jul 09, 2009 11:13 am
pls check the attachments
Attachments
Q1 and 2.doc
Last edited by sanjib on Fri Jul 10, 2009 12:03 pm, edited 2 times in total.

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by ssmiles08 » Thu Jul 09, 2009 11:34 am
IMO E.

1)the ratio of OP = 1x, ratio of OQ = 2x

r = 3x.

Insufficient. x could be any number.

2) doesn't give any information about radius other than AP = BP.

together we can draw a right triangle by making r as the hypotenuse: 3x.

OP = 1x

and figure out AP as 2*sqrt(2)x

But this is not sufficient either as we have no information on x.

For problem number 2, you are missing the second requirement.

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### 2nd prob

by brick2009 » Sat Jul 11, 2009 7:34 am

1.) L(arc) = ((r deg)360) x 2*pi*radius

L(arcc) = 18, but we have 2 variables, angle R and radius ---> insuf

2.) Same equation... L(arc) cant be calculated as radius is unknow..--> insuf

When you combine the two.. r=s=> its an equilateral triangle..as bottom two angles are S...

So angle is 60..L(arc) = 18...only Radius unknow... hence u can find the circumference

So C..

[/list]

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### IMO

by kc_raj » Sat Jul 11, 2009 7:49 am
IMO both E,

brick why angle is 60 why not both r=s=45,

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by gmat740 » Sat Jul 11, 2009 9:33 am
brick why angle is 60 why not both r=s=45,
dude,it is an equilateral triangle.

all angles are equal = 60

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by crackthetest » Sat Jul 11, 2009 9:51 am
IMO,

Q1: E

(ssmiles - the length of AP I calculated to be sqrt(2)x, ( b^2 = 3x^2 - x^2) )

Q2: C (same method as brick)

You can calculate without working for XOY, but yes angle(XOY) = 2* angle(XYZ).

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by Naruto » Sun Jul 12, 2009 1:30 am

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### IMO

by kc_raj » Sun Jul 12, 2009 7:14 am

IMO 1) E,
2) C

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by tohellandback » Sun Jul 12, 2009 7:17 am
IMO E,C
for qstn1) neither of the statements are sifficient. and combining both, you can draw any number of circles with that ratio.

for qstn2: draw a chord parallel to the side containing two angles s.
the triangle formed is an equilateral triangle. Just by symmetry you can tell that the circumference will be 27
The powers of two are bloody impolite!!

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by real2008 » Sun Jul 12, 2009 12:13 pm

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### 2nd Question...

by mgshorrGMAT » Thu Jul 16, 2009 2:08 am
Using Statement 2, You can determine that it is a 60-60-60 Triangle...Therefore the arc XZ is 120 degrees, or 1/3 of the circle...Using Statement 1, you are told that the remaining portion of the circle, the other 2/3 is = to 18...

2/3=18 so 3/3=27...Answer should be C....

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