Need help with this concept:
When n is odd
n^3-n or (n-1)n(n+1) is divisible by 24
Let's take n equal to 1
1^3-1 = 0
1 is odd
0 is even
2 is even
Thank you for your help!
Question about consecutive numbers
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- Brent@GMATPrepNow
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I'm not sure what you're asking with the part in blue, but I can address the statement that (n-1)n(n+1) is divisible by 24loadedx wrote:Need help with this concept:
When n is odd
n^3-n or (n-1)n(n+1) is divisible by 24
Let's take n equal to 1
1^3-1 = 0
1 is odd
0 is even
2 is even
Thank you for your help!
First notice that n-1, n, and n+1 represent 3 consecutive integers (for any integer n)
Next, there's a nice rule that says "among any n integers, one the numbers will be divisible by n"
So, one of the three integers (n-1, n, and n+1) will be divisible by 3
Next notice that, if n is odd, then n-1 and n+1 are even (i.e., divisible by 2)
Also notice that every second even number is divisible by 4.
So, of the 3 consecutive integers, we know that one is divisible by 2, one is divisible by 3, and one is divisible by 4
This means that their product must be divisible by (2)(3)(4) or 24
Cheers,
Brent
Brent, thank you very much! Now the concept is clearer.
About the part in blue. The point I was trying to make is the following. If a problem is asking:
"n is odd, is (n-1)n(n+1) is divisible by 24?"
I can not answer this question, unless I know that n is positive.
Do you agree with me?
About the part in blue. The point I was trying to make is the following. If a problem is asking:
"n is odd, is (n-1)n(n+1) is divisible by 24?"
I can not answer this question, unless I know that n is positive.
Do you agree with me?
GMAT/MBA Expert
- Brent@GMATPrepNow
- GMAT Instructor
- Posts: 16207
- Joined: Mon Dec 08, 2008 6:26 pm
- Location: Vancouver, BC
- Thanked: 5254 times
- Followed by:1268 members
- GMAT Score:770
No, (n-1)n(n+1) is divisible by 24 for any integer nloadedx wrote:Brent, thank you very much! Now the concept is clearer.
About the part in blue. The point I was trying to make is the following. If a problem is asking:
"n is odd, is (n-1)n(n+1) is divisible by 24?"
I can not answer this question, unless I know that n is positive.
Do you agree with me?
First of all, 0 is divisible by 24. Some students don't like this, but the formal definition of divisibility says that integer N is divisible by integer D if N = kD for some integer k.
So, 0 is divisible by 24 since 0 = 0(24)
Using the formal definition, we can also show that the rule applies to negative numbers as well.
For example, -24 is divisible by 24 since -24 = (-1)(24)
Having said all of that, in most GMAT questions, the numbers are typically restricted to positive values (to make things easier for us).
Cheers,
Brent