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GMAT Prep Test 2 - Problem Solving

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by v_schame » Tue Jan 29, 2013 2:48 pm
Hi,

I did test prep 2 and I can't seem to get to the right answer. I tried several things, but I'm not sure I'm 100% of the f(x)=f(x-1) -> does this mean to replace the x values in each equation with x-1?

For which of the following functions f is f(x)=f(1-x) for all x?

A - f(x)=1-x
B - f(x)=1-x^2
C - f(x)=x^2-(1-x)^2
D - f(x)=x^2(1-x)^2
E - f(x)=x/(1-x)

The correct answer is d).

Thanks!

V
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Source: — Problem Solving |

by Brent@GMATPrepNow » Tue Jan 29, 2013 3:23 pm
v_schame wrote: For which of the following functions f is f(x)=f(1-x) for all x?

A - f(x)=1-x
B - f(x)=1-x^2
C - f(x)=x^2-(1-x)^2
D - f(x)=x^2(1-x)^2
E - f(x)=x/(1-x)
Let's try plugging in an easy value for x. How about x = 0.
So, we can reword the question as, For which of the following functions is f(0)=f(1-0)
In other words, we're looking for a function such that f(0) = f(1)

A) f(x)=1-x
f(0)=1-0 = 1
f(1)=1-1 = 0
Since f(0) doesn't equal f(1), eliminate A

B) f(x) = 1 - x^2
f(0) = 1 - 0^2 = 1
f(1) = 1 - 1^2 = 0
Since f(0) doesn't equal f(1), eliminate B

C) f(x) = x^2 - (1-x)^2
f(0) = 0^2 - (1-0)^2 = -1
f(1) = 1^2 - (1-1)^2 = 1
Since f(0) doesn't equal f(1), eliminate C

D) f(x) = x^2(1-x)^2
f(0) = 0^2(1-0)^2 = 0
f(1) = 1^2(1-1)^2 = 0
Since f(0) equals f(1), keep D for now

E) f(x) = x/(1-x)
f(0) = 0/(1-0) = 0
f(1) = 1/(1-1) = undefined
Since f(0) doesn't equal f(1), eliminate E

Since only D satisfies the condition that f(x)=f(1-x) when x=0, the correct answer is D

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
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by varun289 » Fri Feb 01, 2013 10:56 am
v_schame wrote:
For which of the following functions f is f(x)=f(1-x) for all x?

A - f(x)=1-x
B - f(x)=1-x^2
C - f(x)=x^2-(1-x)^2
D - f(x)=x^2(1-x)^2
E - f(x)=x/(1-x)
these type questions are simple but thought - create illusions
put x=1-x in FX u get x=1-x so leave that , A gone
B- (1-x)^2 = make lots of wordy , leave that
c- another wordy forget
D-yes put X =1-x u get same figure as (1-x)^2X^2
Click and move on

simple coollll
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