Can anybody help in understanding the logic behind this question??
Does the line y = ax + b pass through the point (2,5)?
(1) When it is reflected around the x-axis, the line passes through the point (1,-6).
(2) When it is reflected around the y-axis, the line passes through the point (-3,4)
What is the reflection concept??????
Concept problem
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Hi,
Any point (p,q) reflected in X- axis will become (p,-q)
Similarly (p,q) reflected in Y-axis becomes (-p,q)
From(1):
Line y = ax+b passes through (1,6)
Not sufficient
From(2):
Line y = ax+b passes through (3,4)
Not sufficient
Both(1) and (2) : line y = ax+b passes through (1,6) and (3,4). So, its equation is x+y = 7
(2,5) passes though this line.
Hence, C
Any point (p,q) reflected in X- axis will become (p,-q)
Similarly (p,q) reflected in Y-axis becomes (-p,q)
From(1):
Line y = ax+b passes through (1,6)
Not sufficient
From(2):
Line y = ax+b passes through (3,4)
Not sufficient
Both(1) and (2) : line y = ax+b passes through (1,6) and (3,4). So, its equation is x+y = 7
(2,5) passes though this line.
Hence, C
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well good question indeed.Liked this concept here.
the question asks for 5=2a+b ?
a (1,-6) = (1,6) in quadrant 1. line is 6= a+b. not sufficient.
b (3,-4) = (3,4) in quadrant 1. line is 4= 3a+b. not sufficient.
a+b gives
solving two equations above gives a=-1 and b=7
thus 5=2(-1) + 7. hence true.
C it is.
the question asks for 5=2a+b ?
a (1,-6) = (1,6) in quadrant 1. line is 6= a+b. not sufficient.
b (3,-4) = (3,4) in quadrant 1. line is 4= 3a+b. not sufficient.
a+b gives
solving two equations above gives a=-1 and b=7
thus 5=2(-1) + 7. hence true.
C it is.
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