If p is a positive integer and 10p/96
is an integer, then the minimum
number of prime factors p could have is
(A) One
(B) Two
(C) Three
(D) Four
(E) Five
I had 5. OA is 2. It didn't say different. How is everyone else interpreting this question.
Number prop
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96 = 2^5 * 3
10p/96 = 2*5*p/96
for above equation to be an integer p = 2^4 *3
There are 2 prime factors - 2 and 3
10p/96 = 2*5*p/96
for above equation to be an integer p = 2^4 *3
There are 2 prime factors - 2 and 3
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- Anurag@Gurome
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10p/96 = 5p/48 ---> An integeryellowho wrote:If p is a positive integer and 10p/96 is an integer, then the minimum number of prime factors p could have is
(A) One
(B) Two
(C) Three
(D) Four
(E) Five
For 5p/48 to be integer, p has to be a multiple of 48 = (2^4)*(3)
Hence, p must have at least 2 prime factors, i.e. 2 and 3.
The correct answer is B.
Anurag Mairal, Ph.D., MBA
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- prachich1987
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The question is not asking us to find DISTINCT prime factors.Anurag@Gurome wrote: 10p/96 = 5p/48 ---> An integer
For 5p/48 to be integer, p has to be a multiple of 48 = (2^4)*(3)
Hence, p must have at least 2 prime factors, i.e. 2 and 3.
The correct answer is B.
It is just asking us to find prime factors.
The minimum no. of prime factors should be 5.
Can you please explain.
Thanks!
Prachi
Prachi