The question is:
Exactly how many show dogs does Sheila have?
(1) Of Sheila's show dogs, exactly 3 have won prizes of at least $500
(2) Of Sheila's show dogs, exactly 40% have not won a prize of $500 or more.
The answer provided is (C) because according to the book 60% represents the 3 that have won prizes and hence you can calculate the no. of dogs.
However the solution assumes that all of Sheila's dogs won a prize. Is this correct? Should the answer not be (E) because we are not told that all of Sheila's dogs have won at least one prize.
Not sure if the provided answer is correct
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The correct answer is C.
A---itself not sufficient since information is provided of only three dogs.
B--itself not sufficient since only the % of dogs is given. The actual number cannot be calculated.
Taking A+B
This means that 60% Total dogs =3; So the total number of dogs can be calculated.
A---itself not sufficient since information is provided of only three dogs.
B--itself not sufficient since only the % of dogs is given. The actual number cannot be calculated.
Taking A+B
This means that 60% Total dogs =3; So the total number of dogs can be calculated.