Nicky and Chadi begin running a race at the same time, though Nicky starts the race 36 meters ahead of Chadi. If Chadi runs at a pace of 5 meters per second and Nicky runs at a pace of only 3 meters per second, how many seconds will Nicky have run by the time Chadi passes him?
(A) 15 seconds
(B) 18 seconds
(C) 25 seconds
(D) 30 seconds
(E) 45 seconds
[spoiler]OA=B[/spoiler]
Source: Manhattan GMAT
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Nicky and Chadi begin running a race at the same time, though Nicky starts the race 36 meters ahead of Chadi. If Chadi
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orthodoxparadox
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Speed of Chadi = 5m/s
Speed of Nicky = 3m/s
Speed by which Chadi catches up with Nicky = 5m/s - 3m/s = 2m/s
Distance that Nicky is initially ahead = 36m
So time taken to catch up = \(\frac{36}{2}\ =\ 18\) B
Speed of Nicky = 3m/s
Speed by which Chadi catches up with Nicky = 5m/s - 3m/s = 2m/s
Distance that Nicky is initially ahead = 36m
So time taken to catch up = \(\frac{36}{2}\ =\ 18\) B
