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GMATPrep Problem .. assign identification
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I guess the answer should be 4536.
This problem is of permutations.
We have total 10 letters [0,1,2,3,4,5,6,7,8,9]
first place can be filled in 9 ways, since 0 is not to be included = 9 ways.
Second place can also be filled in 9 ways, since 0 can be included = 9 ways.
Third place can be filled in 8 ways
Fourth place can be filled in 7 ways.
9*9*8*7 = 4536
Whats the OA?
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How can the answer be 4536?
I would go about this problem in the following way:
1st digit can be arranged in 9 ways (0 not included)
2nd digit can be arranged in 10 ways (0 included)
3rd digit can be arranged in 10 ways (0 included)
4th digit can be arranged in 10 ways (0 included)
Hence total ways = 9*10*10*10 = 9000 ways
We cannot assume that same numbers should not be repeated in different digit places because thats nowhere mentioned in the problem.
If we assume this, then 4536 is the right answer.
Can you please let us know the OA?
Regards
MSD
I would go about this problem in the following way:
1st digit can be arranged in 9 ways (0 not included)
2nd digit can be arranged in 10 ways (0 included)
3rd digit can be arranged in 10 ways (0 included)
4th digit can be arranged in 10 ways (0 included)
Hence total ways = 9*10*10*10 = 9000 ways
We cannot assume that same numbers should not be repeated in different digit places because thats nowhere mentioned in the problem.
If we assume this, then 4536 is the right answer.
Can you please let us know the OA?
Regards
MSD
When the going gets tough, the tough gets going.
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The question explicitly states that "Each number consists of four different digits"msd_2008 wrote:How can the answer be 4536?
I would go about this problem in the following way:
1st digit can be arranged in 9 ways (0 not included)
2nd digit can be arranged in 10 ways (0 included)
3rd digit can be arranged in 10 ways (0 included)
4th digit can be arranged in 10 ways (0 included)
Hence total ways = 9*10*10*10 = 9000 ways
We cannot assume that same numbers should not be repeated in different digit places because thats nowhere mentioned in the problem.
If we assume this, then 4536 is the right answer.
Can you please let us know the OA?
Regards
MSD
No Assumptions!!
Hope this helps.
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Shahab,
This is a permutaion since the order does matter.
Eg: 7586 id is different from 7856 id (even though they have the same digits but the position of the digits make the difference)
Make 4 slots
1st slot can be filled by 9 numbers(since 0 cannot be included)
2nd slot by 9(the first number u have choosen cannot be included but 0 can be the 2nd digit)
3rd slot can be filled by 8 since we cant use the first 2 numbers in the first 2 slots
4th slot by 7 (same reason as above)
So 9*9*8*7 would be 4536
This is a permutaion since the order does matter.
Eg: 7586 id is different from 7856 id (even though they have the same digits but the position of the digits make the difference)
Make 4 slots
1st slot can be filled by 9 numbers(since 0 cannot be included)
2nd slot by 9(the first number u have choosen cannot be included but 0 can be the 2nd digit)
3rd slot can be filled by 8 since we cant use the first 2 numbers in the first 2 slots
4th slot by 7 (same reason as above)
So 9*9*8*7 would be 4536
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Easier way to understand this would be
Take 0,1,2 How many different 3 digit identifcation numbers can be formed where 0 cannot be the first digit(since its 012 is not valid)
0,1,2
Brute force listing of possibilities:
102
120
201
210
4 numbers
Permutation/counting principle method:
1st slot: 2
2nd slot: 2
3rd slot:1
2*2*1 = 4
Hope this helps!
Take 0,1,2 How many different 3 digit identifcation numbers can be formed where 0 cannot be the first digit(since its 012 is not valid)
0,1,2
Brute force listing of possibilities:
102
120
201
210
4 numbers
Permutation/counting principle method:
1st slot: 2
2nd slot: 2
3rd slot:1
2*2*1 = 4
Hope this helps!