MGMAT, Inequalities!

This topic has expert replies
Senior | Next Rank: 100 Posts
Posts: 74
Joined: Wed Apr 06, 2011 8:35 pm
Followed by:1 members

MGMAT, Inequalities!

by Ahmed MS » Fri Oct 21, 2011 11:32 pm
Q: If x>y, x<6, and y>-3, what is the largest prime number that could be equal to x+y? ( source: Manhattan equation, chapter 12 problem set).


The answer is 11 but I failed to understand the explanation, please help.

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 3835
Joined: Fri Apr 02, 2010 10:00 pm
Location: Milpitas, CA
Thanked: 1854 times
Followed by:523 members
GMAT Score:770

by Anurag@Gurome » Fri Oct 21, 2011 11:38 pm
Ahmed MS wrote:Q: If x>y, x<6, and y>-3, what is the largest prime number that could be equal to x+y? ( source: Manhattan equation, chapter 12 problem set).
-3 < y < x < 6

To find the largest prime number which is equal to (x + y), we have to maximize both x and y such that their sum is a prime number. Note that this does not mean that x and y have to be integer.

Maximum possible value for x and y is just less than 6.
Hence, maximum possible sum of x and y will be just less than (6 + 6) = 12

The largest prime number less than 12 is 11.
If we take x = 5.9 and y = 5.1, (x + y) = (5.9 + 5.1) = 11
Hence, it is possible that (x + y) can be equal to 11.

Therefore, 11 is the largest prime number that could be equal to (x + y).
Anurag Mairal, Ph.D., MBA
GMAT Expert, Admissions and Career Guidance
Gurome, Inc.
1-800-566-4043 (USA)

Join Our Facebook Groups
GMAT with Gurome
https://www.facebook.com/groups/272466352793633/
Admissions with Gurome
https://www.facebook.com/groups/461459690536574/
Career Advising with Gurome
https://www.facebook.com/groups/360435787349781/

Senior | Next Rank: 100 Posts
Posts: 74
Joined: Wed Apr 06, 2011 8:35 pm
Followed by:1 members

by Ahmed MS » Sat Oct 22, 2011 12:03 am
Wow! Thanks a lot Anurag! That is so easy and simple.

Senior | Next Rank: 100 Posts
Posts: 74
Joined: Wed Apr 06, 2011 8:35 pm
Followed by:1 members

by Ahmed MS » Sat Oct 22, 2011 12:05 am
Wow! Thanks a lot Anurag! That is so easy and simple.