(1) Not sufficient. x could be zero, and y=-1. Or x could be +/-1, in which case y=0. Or x^2 = y^2 = 1/2. Etc...prata wrote:If y is not equal to 1, is x = 1?
1. x2 + y2 = 1
2. y = 1 - x
(2) Not sufficient. y could be any value, except 1. Thus x can be any value except 0.
(1) & (2) combined: This is sufficient. Combining the two statements:
x^2 + (1-x)^2 = 1
Then x^2 + (1 - 2x + x^2) = 1
2x^2 - 2x = 0
x(2x - 2) = 0. So x = 0 or x = 1, but x cannot equal 0 from (2) above. Hence, x = 1 and y = 0.
Answer is C.




















