For how many integers n is n + n = n.n ?
a) None
b) One
c) Two
d) Three
e) More than three.
Please assist with above problem.
For how many integers n is n + n = n.n ? a) None b) One c)
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Hi alanforde800Maximus,
I assume that the question is meant to ask "for how many integers N is N+N = (N)(N)?"
In simpler terms, "which number, when added to itself, equals the square of itself?"
This question can be solved with a bit of 'brute force'
0+0 = (0)(0)
2+2 = (2)(2)
Final Answer: C
GMAT assassins aren't born, they're made,
Rich
I assume that the question is meant to ask "for how many integers N is N+N = (N)(N)?"
In simpler terms, "which number, when added to itself, equals the square of itself?"
This question can be solved with a bit of 'brute force'
0+0 = (0)(0)
2+2 = (2)(2)
Final Answer: C
GMAT assassins aren't born, they're made,
Rich
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When you get a chance, please edit the question so that it reads as Rich suggests.alanforde800Maximus wrote:For how many integers n is n + n = (n)(n) ?
a) None
b) One
c) Two
d) Three
e) More than three.
Another approach:
Given: n + n = (n)(n)
Simplify: 2n = n²
Subtract 2n from both sides to get: n² - 2n = 0
Factor: n(n - 2) = 0
So, EITHER n = 0 OR n = 2
There are two solutions.
Answer: C
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If we have
n + n = n * n
or
2n = n²
We can find any nonzero solutions by dividing by n:
2 = n
and we can find any zero solutions by trying 0:
2*0 = 0*0
So our two solutions are n = 0 and n = 2.
n + n = n * n
or
2n = n²
We can find any nonzero solutions by dividing by n:
2 = n
and we can find any zero solutions by trying 0:
2*0 = 0*0
So our two solutions are n = 0 and n = 2.
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Simplifying the equation, we have:alanforde800Maximus wrote:For how many integers n is n + n = n.n ?
a) None
b) One
c) Two
d) Three
e) More than three.
2n = n^2
n^2 - 2n = 0
n(n - 2) = 0
n = 0 or n = 2, so there are two possible integer values for n.
Answer: C
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