Data Sufficiency

If five more scouts are added to a scout camp group, would the scout leader be able to divide the group into teams of 10 scouts each without any remainder?
(1) Initially, the number of scouts in the group was not divisible by ten.
(2) If 25 scouts are added to the group, the group can be divided into teams of 10 without any remainder.

I would have to say B.

As statement 1 says the orginal number isn't divisible by 10. So say 15 and add 5 then it is. But if it's 11 and add 5 then it isn't.

statement 2 you are adding 25. So if you have 15 and add 25 then it's 40 and meets the factor and then 15 plus 5 is divisible by 10. This would work with any number that you could start with that makes it divisible by 10. So i started with 25 and 25 that's 50; then 25 plus 5 is 30 fits.

Am i right?

seal4913 wrote:I would have to say B.

As statement 1 says the orginal number isn't divisible by 10. So say 15 and add 5 then it is. But if it's 11 and add 5 then it isn't.

statement 2 you are adding 25. So if you have 15 and add 25 then it's 40 and meets the factor and then 15 plus 5 is divisible by 10. This would work with any number that you could start with that makes it divisible by 10. So i started with 25 and 25 that's 50; then 25 plus 5 is 30 fits.

Am i right?

Yes, you are right, seal4913. Just keep it up!

IMO B.

same approach as explained by seal