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-100 divided by 30 - Remainder ?

Expert replies
by gmattesttaker2 » Sun Feb 16, 2014 8:19 pm
Hello,

Can you please tell me how to solve this:

When m is divided by d, the result is q and the remainder is r. If m = dq + r,
what is the remainder when -100 is divided by 30?

(A) 30
(B) 10
(C) 0
(D) -10
(E) -20

OA: D

Thanks,
Sri
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Source: — Problem Solving |

by GMATGuruNY » Sun Feb 16, 2014 8:53 pm
gmattesttaker2 wrote:Hello,

Can you please tell me how to solve this:

When m is divided by d, the result is q and the remainder is r. If m = dq + r,
what is the remainder when -100 is divided by 30?

(A) 30
(B) 10
(C) 0
(D) -10
(E) -20

OA: D

Thanks,
Sri
Ignore this problem.
On the GMAT, problems about remainders are restricted to NONNEGATIVE INTEGERS.
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by Abhishek009 » Mon Feb 17, 2014 7:09 am
gmattesttaker2 wrote:Hello,

Can you please tell me how to solve this:

When m is divided by d, the result is q and the remainder is r. If m = dq + r,
what is the remainder when -100 is divided by 30?

(A) 30
(B) 10
(C) 0
(D) -10
(E) -20

OA: D

Thanks,
Sri
Though GMATGuruNY has sugegsted that this is out of scope of GMAT Problem still would like to attempt it out of curiosity.

m = dq + r

Or, -100 = 30*-3 -10

Hence r = -10

IMO (D)..
Abhishek
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by Brent@GMATPrepNow » Mon Feb 17, 2014 7:52 am
Abhishek009 wrote:
Though GMATGuruNY has sugegsted that this is out of scope of GMAT Problem still would like to attempt it out of curiosity.

m = dq + r

Or, -100 = 30*-3 -10

Hence r = -10

IMO (D)..
Here's how the GMAT test-makers define remainders:

If x and y are positive integers, there exist unique integers q and r, called the quotient and remainder, respectively, such that y = xq + r and 0 < r < x.

Notice that the remainder must be greater than or equal to zero AND the remainder must be less than the divisor.
So, we get: 0 < remainder < -100.. Hmmm, the number must be greater than or equal to zero AND less than -100
Obviously, there's no such number.


Also notice that negative values take away the conceptual nature of remainders. Typically, we can get remainders when we're trying to divide some quantity into equal amounts. So, for example, if we have 17 balls and we want to divide them equally among 3 children, then we can give each child 5 balls, at which point we have 2 balls remaining. Thus 2 is the remainder.

What happens if we have -17 balls and want to divide them equally among 3 children? How does that work? How many balls does each child get?
Well, we could say that each child gets -5 balls, and there are -2 balls remaining. Here, (-5)(3) + (-2) = -17
We could say that each child gets -6 balls, and there is 1 ball remaining. Here, (-6)(3) + 1 = -17
So, what is the true remainder?

Of course, neither of these scenarios make sense. So, as you can see, the entire concept of remainders falls apart with negative values.

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
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by [email protected] » Mon Feb 17, 2014 4:35 pm
Hi Sri,

I agree with Mitch and Brent - the GMAT would never ask you this type of question. What is the source of this question? I only ask because there are many 3rd-party sources that provide questions/concepts/info about the GMAT that are completely wrong and you (as well as all other GMAT preppers) need to be wary of these resources.

GMAT assassins aren't born, they're made,
Rich
Contact Rich at [email protected]
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