On an aerial photograph, the surface of a pond appears as circular region of radius 16/7 inch. If a distance of 1 inch on the photograph corresponds to an actual distance of 2 miles, which of the following is the closest estimate of the actual surface area of the pond, in square miles?
A. 1.3
B. 2.4
C. 3.0
D. 3.8
E. 5.0
Looks easy..but want to confirm answer
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I think you got the question wrong. With those numbers none of the answers make sense. Instead of 16/7 inches i think it should be 7/16 inches.... In which case the answer is 2.4.
7/16 inches * 2 miles/inch = 14/16 = 7/8.
Now:
Pi*( 7/8 )^2 = ~3*(49/64)= ~ 150/64 = ~75/32 or somewhere around 2.5, but we know it's less than 3 and greater than 2.
The only answer that fits is B... 2.4.
7/16 inches * 2 miles/inch = 14/16 = 7/8.
Now:
Pi*( 7/8 )^2 = ~3*(49/64)= ~ 150/64 = ~75/32 or somewhere around 2.5, but we know it's less than 3 and greater than 2.
The only answer that fits is B... 2.4.
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mav,
With the numbers you posted I am getting 2.9, which is about 3.0. Let us know the OA.
With the numbers you posted I am getting 2.9, which is about 3.0. Let us know the OA.
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Actually, if you use the numbers he posted you get ~60.
16/7 inches * 2 miles/inch = 32/7 miles
The surface area in square miles will be: pi(32/7)^2
which is pi(1024/49) or about 3000/50 = ~60
If you use a calculator and a few digits of pi, you get around 65.6.
16/7 inches * 2 miles/inch = 32/7 miles
The surface area in square miles will be: pi(32/7)^2
which is pi(1024/49) or about 3000/50 = ~60
If you use a calculator and a few digits of pi, you get around 65.6.
AleksandrM wrote:mav,
With the numbers you posted I am getting 2.9, which is about 3.0. Let us know the OA.
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one needs to convert inches to miles and then square it. we get 2.4 approx with that.
and its 7/16 and not 16/7.
and its 7/16 and not 16/7.
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