milk
This topic has expert replies
- goyalsau
- Legendary Member
- Posts: 866
- Joined: Mon Aug 02, 2010 6:46 pm
- Location: Gwalior, India
- Thanked: 31 times
Timer
00:00
Your Answer
A
B
C
D
E
Global Stats
If k litres of a solution of x% milk, 2k litres of a solution of y% milk, and 3k litres of a solution of (x + y)% milk are all mixed in a vessel, the resultant solution has 50% milk. Find the resultant concentration of milk when 40 litres of the first solution and 50 litres of the second solution are mixed.
Saurabh Goyal
[email protected]
-------------------------
EveryBody Wants to Win But Nobody wants to prepare for Win.
[email protected]
-------------------------
EveryBody Wants to Win But Nobody wants to prepare for Win.
GMAT/MBA Expert
- Rahul@gurome
- GMAT Instructor
- Posts: 1179
- Joined: Sun Apr 11, 2010 9:07 pm
- Location: Milpitas, CA
- Thanked: 447 times
- Followed by:88 members
When k, 2k and 3k liters are mixed:
- Total amount of the resultant solution = (k + 2k + 3k) liters = 6k liters
Total amount of milk in the solution = (kx/100 + 2ky/100 + 3k(x + y)/100) liters = k*(4x + 5y)/100 liters
Percentage of milk in the solution = 100*[k*(4x + 5y)/100]/(6k) = (4x + 5y)/6
According to question, (4x + 5y)/6 = 50 => (4x + 5y) = 300
- Total amount of the resultant solution = (40 + 50) liters = 90 liters
Total amount of milk in the solution = (40x/100 + 50y/100) liters = (40x + 50y)/100 liters
Percentage of milk in the solution = 100*[(40x + 50y)/100]/(90) = (4x + 5y)/9 = 300/9 = 100/3 = 33.33
Rahul Lakhani
Quant Expert
Gurome, Inc.
https://www.GuroMe.com
On MBA sabbatical (at ISB) for 2011-12 - will stay active as time permits
1-800-566-4043 (USA)
+91-99201 32411 (India)
Quant Expert
Gurome, Inc.
https://www.GuroMe.com
On MBA sabbatical (at ISB) for 2011-12 - will stay active as time permits
1-800-566-4043 (USA)
+91-99201 32411 (India)
- shovan85
- Community Manager
- Posts: 991
- Joined: Thu Sep 23, 2010 6:19 am
- Location: Bangalore, India
- Thanked: 146 times
- Followed by:24 members
k(x/100) + 2k(y/100) + 3k[(x+y)/100] = 6k(50/100)goyalsau wrote:If k litres of a solution of x% milk, 2k litres of a solution of y% milk, and 3k litres of a solution of (x + y)% milk are all mixed in a vessel, the resultant solution has 50% milk. Find the resultant concentration of milk when 40 litres of the first solution and 50 litres of the second solution are mixed.
=> 4kx/100 + 5ky/100 = 300k/100
=> x(0.04) + y(0.05) = 3
40 lts type 1 contains .4x milk
50 lts type 2 contains .5y milk
Thus 0.4x+0.5y = 10 [x(0.04) + y(0.05)] = 10*3 = 30 lts
Thus concentration = 30/90 = 1/3 = 33.33%
If the problem is Easy Respect it, if the problem is tough Attack it