Grace has 16 jellybeans in her pocket. She has 8 red ones, 4 green ones, and 4 blue ones. What is the minimum number of jellybeans she must take out of her pocket to ensure that she has one of each color?
4
8
12
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16
jellybeans
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- GMATGuruNY
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To guarantee that one of each color is chosen, we have to determine the worst-case-scenario: the maximum number of jellybeans that could be selected without getting one of each color.GmatKiss wrote:Grace has 16 jellybeans in her pocket. She has 8 red ones, 4 green ones, and 4 blue ones. What is the minimum number of jellybeans she must take out of her pocket to ensure that she has one of each color?
4
8
12
13
16
If all of the 8 red jellybeans and all of the 4 green (or blue) jellybeans are selected, then 8+4=12 jellybeans will be selected without getting one of each color.
The next jellybean selected - the 13th jellybean -- will have to be of the one remaining color.
Thus, to guarantee that one of each color is selected, 13 jellybeans must be selected.
The correct answer is D.
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I unlock the best way for YOU to solve problems.
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13(D).GMATGuruNY wrote:To guarantee that one of each color is chosen, we have to determine the worst-case-scenario: the maximum number of jellybeans that could be selected without getting one of each color.GmatKiss wrote:Grace has 16 jellybeans in her pocket. She has 8 red ones, 4 green ones, and 4 blue ones. What is the minimum number of jellybeans she must take out of her pocket to ensure that she has one of each color?
4
8
12
13
16
If all of the 8 red jellybeans and all of the 4 green (or blue) jellybeans are selected, then 8+4=12 jellybeans will be selected without getting one of each color.
The next jellybean selected - the 13th jellybean -- will have to be of the one remaining color.
Thus, to guarantee that one of each color is selected, 13 jellybeans must be selected.
The correct answer is D.