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by GmatKiss » Sat Aug 13, 2011 1:55 pm
Grace has 16 jellybeans in her pocket. She has 8 red ones, 4 green ones, and 4 blue ones. What is the minimum number of jellybeans she must take out of her pocket to ensure that she has one of each color?

4
8
12
13
16
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by GMATGuruNY » Sat Aug 13, 2011 3:22 pm
GmatKiss wrote:Grace has 16 jellybeans in her pocket. She has 8 red ones, 4 green ones, and 4 blue ones. What is the minimum number of jellybeans she must take out of her pocket to ensure that she has one of each color?

4
8
12
13
16
To guarantee that one of each color is chosen, we have to determine the worst-case-scenario: the maximum number of jellybeans that could be selected without getting one of each color.

If all of the 8 red jellybeans and all of the 4 green (or blue) jellybeans are selected, then 8+4=12 jellybeans will be selected without getting one of each color.
The next jellybean selected - the 13th jellybean -- will have to be of the one remaining color.
Thus, to guarantee that one of each color is selected, 13 jellybeans must be selected.

The correct answer is D.
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by GmatKiss » Sun Aug 14, 2011 11:21 am
OA:D
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by czarczar » Tue Aug 16, 2011 9:47 pm
GMATGuruNY wrote:
GmatKiss wrote:Grace has 16 jellybeans in her pocket. She has 8 red ones, 4 green ones, and 4 blue ones. What is the minimum number of jellybeans she must take out of her pocket to ensure that she has one of each color?

4
8
12
13
16
To guarantee that one of each color is chosen, we have to determine the worst-case-scenario: the maximum number of jellybeans that could be selected without getting one of each color.

If all of the 8 red jellybeans and all of the 4 green (or blue) jellybeans are selected, then 8+4=12 jellybeans will be selected without getting one of each color.
The next jellybean selected - the 13th jellybean -- will have to be of the one remaining color.
Thus, to guarantee that one of each color is selected, 13 jellybeans must be selected.

The correct answer is D.
13(D).
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