4x=5y=10z, what is the value of x+y+z?
1) x-y=6
2) y+z=36
OA is D
x+y+z
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1) x - y = 6 implies x = y + 6grandh01 wrote:4x=5y=10z, what is the value of x+y+z?
1) x-y=6
2) y+z=36
OA is D
So, 4x = 5y implies 4(y + 6) = 5y or 4y + 24 = 5y or y = 24
5y = 10z implies 5 * 24 = 10z or z = 12
We know the values of y and z, so we can find the value of x and hence can fine the value of x + y + z; SUFFICIENT.
2) y + z = 36 implies y = 36 - z
So, 5y = 10z implies 5(36 - z) = 10z or 180 = 15z or z = 12
y = 36 - 12 = 24
We know the values of y and z, so we can find the value of x and hence can fine the value of x + y + z; SUFFICIENT.
The correct answer is D.
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Don't solve.grandh01 wrote:4x=5y=10z, what is the value of x+y+z?
1) x-y=6
2) y+z=36
OA is D
Determine only whether there is SUFFICIENT information to solve.
Statement 1: x-y=6
Since 4x=5y, we have two variables and two distinct linear equations, enabling us to solve for x and y.
Since 5y=10z, the value of y will give us the value of z.
SUFFICIENT.
Statement 2: y+z=36
Since 5y=10z, we have two variables and two distinct linear equations, enabling us to solve for y and z.
Since 4x=5y, the value of y will give us the value of x.
SUFFICIENT.
The correct answer is D.
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This is a nice question because the target question asks us to find the sum of 3 variables, and when it comes to solving systems with three variables, we typically need 3 different equations. At first glance, it appears that we are given only 1 equation (4x=5y=10z) when, in fact, there are 3 different equations here:grandh01 wrote:4x=5y=10z, what is the value of x+y+z?
1) x-y=6
2) y+z=36
1) 4x=5y
2) 5y=10z
3) 4x=10z
If we make the mistake of believing that 4x=5y=10z is a single equation with 3 variables, we may erroneously conclude that we need two more equations to answer the target question. If we make this mistake, we will incorrectly conclude that each statement on its own is insufficient.
That's all I wanted to say about that.
Mitch and Anurag already provided great explanations (as always). I just wanted to make that observation.
Cheers,
Brent