Source: MGMAT
Is x > 0?
(1) |x + 3| < 4
(2) |x - 3| < 4
Answer: E
Can someone please explain the best way to look at the combined inequality? This is how MGMAT explains it:
If we combine the solutions from statements (1) and (2) we get an overlapping range of -1 < x < 1. We still can't tell whether x is positive.
IS THIS BECAUSE WE DON'T KNOW THAT X IS AN INTEGER, THEREFORE, COULD BE -1/4 OR 0 (WHICH IS NOT POS OR NEG)?
Is x > 0?
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you are right. its because x can still be 0 or negative or positive.missrochelle wrote: IS THIS BECAUSE WE DON'T KNOW THAT X IS AN INTEGER, THEREFORE, COULD BE -1/4 OR 0 (WHICH IS NOT POS OR NEG)?
Since there are more than one options, the statement is INSUFFICIENT.
Hope this helps!!
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|x + 3| < 4
case 1: (x + 3 )< 4
= x <1
here X can be greater than zero or less than zero. SO Insufficient
case 2 : - ( x+3) <4
-x -3 <4
-x<7
x> -7
Here again X can be greater than Zero or less than zero.
So st 1 is insufficient.
st 2 : |x - 3| < 4
case 1 : x-3 <4
x< 7
We can have X greater than or less than 0 . Insufficient
case 2: -(x-3) <4
-x+3 <4
-x< 1
x>-1
Again we can have X greater than or lesser than 0.
Combining both the statements we have -1<x<7, the sts hold true. But again X can be greater than or less than zero
Example : X= -0.5
|x - 3| < 4
|-0.5-3| = 3.5 which is less than 4
Now X= 0.5
|0.5 -3|= 2.5 <4 YES.
Here we see , we get inconsistent answers.
so Pick E as -1<X<7
case 1: (x + 3 )< 4
= x <1
here X can be greater than zero or less than zero. SO Insufficient
case 2 : - ( x+3) <4
-x -3 <4
-x<7
x> -7
Here again X can be greater than Zero or less than zero.
So st 1 is insufficient.
st 2 : |x - 3| < 4
case 1 : x-3 <4
x< 7
We can have X greater than or less than 0 . Insufficient
case 2: -(x-3) <4
-x+3 <4
-x< 1
x>-1
Again we can have X greater than or lesser than 0.
Combining both the statements we have -1<x<7, the sts hold true. But again X can be greater than or less than zero
Example : X= -0.5
|x - 3| < 4
|-0.5-3| = 3.5 which is less than 4
Now X= 0.5
|0.5 -3|= 2.5 <4 YES.
Here we see , we get inconsistent answers.
so Pick E as -1<X<7