Investment, XY plane
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- amit2k9
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DS 3
a xr/100 = (24000-x)*7/100 two variables x and r. not sufficient.
b x*5/100 = (24000-x)*7/100 only one variable x. sufficient.
B it is.
a xr/100 = (24000-x)*7/100 two variables x and r. not sufficient.
b x*5/100 = (24000-x)*7/100 only one variable x. sufficient.
B it is.
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- amit2k9
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DS2
a z can be 1 or 5 for t = -3 or -3/5. not sufficient.
b t= -5,-6 or so z = 3/5 or 1/2 thus always a ratio.
Hence B.
a z can be 1 or 5 for t = -3 or -3/5. not sufficient.
b t= -5,-6 or so z = 3/5 or 1/2 thus always a ratio.
Hence B.
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- amit2k9
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- abidshariff
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For DS2...its E...
zt <-3, is z<4?
by using a i.e z<9, we don't know anything about t..so z can be < or > 4.
now take b. say t=-5(t<-4), and z=3, so zt=-15<-3, take z=5 zt=-25<-3. So z can be < or >4
So C is clearly not the ans as z=3,5<9.
So E
zt <-3, is z<4?
by using a i.e z<9, we don't know anything about t..so z can be < or > 4.
now take b. say t=-5(t<-4), and z=3, so zt=-15<-3, take z=5 zt=-25<-3. So z can be < or >4
So C is clearly not the ans as z=3,5<9.
So E
For DS 3, Ans is C and not B. Without stmt 1, how can you assume that the interest on both amounts are equal?amit2k9 wrote:DS 3
a xr/100 = (24000-x)*7/100 two variables x and r. not sufficient.
b x*5/100 = (24000-x)*7/100 only one variable x. sufficient.
B it is.
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- Treker
- Treker