What is the value of integer J?
1. |J| = J^{-1}
2. J^J = 1
integers
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1) |J| = J^{-1}daretodream wrote:What is the value of integer J?
1. |J| = J^{-1}
2. J^J = 1
|J| is always +ve
J^{-1} should be +ve always
J is positive
j=1
Sufficient
2) J = +/- 1 ; insufficient
A
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daretodream wrote:What is the value of integer J?
1. |J| = J^{-1}
2. J^J = 1
s1)first statement says |J| = 1/J
the only value that is possible is1, so SUFF
s2)second statement
J^J = 1
J could be 0 or 1. 1^1 = 1 , 0^0=1
so INSUFF
hence A
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IMO B
1. can be either (-1/1 = -1) or (1/1 = 1)
2. only positive 1 can satisfy this equation, because 0^0 is undeffined and it can't be -1 because it has an odd exponent[/spoiler]
1. can be either (-1/1 = -1) or (1/1 = 1)
2. only positive 1 can satisfy this equation, because 0^0 is undeffined and it can't be -1 because it has an odd exponent[/spoiler]
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Yeah I am of the same view that 0^0 is indeterminate....November Rain wrote:IMO B
1. can be either (-1/1 = -1) or (1/1 = 1)
2. only positive 1 can satisfy this equation, because 0^0 is undeffined and it can't be -1 because it has an odd exponent[/spoiler]
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option 1
|J| = J^{-1}
=> J*|J|=1
J can only have one value that is 1. Hence suff
option 2
J^J = 1
=>j=+1 or -1
insufficient
OA is A
|J| = J^{-1}
=> J*|J|=1
J can only have one value that is 1. Hence suff
option 2
J^J = 1
=>j=+1 or -1
insufficient
OA is A
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A is sufficient everbody agrees
B I was thinking that it was J raise to J and not sqr(J).
J^J = J^0 implies J=0.
when we resubstitute, 0^0 is indeterminate.
Hence A
Good Problem !!
B I was thinking that it was J raise to J and not sqr(J).
J^J = J^0 implies J=0.
when we resubstitute, 0^0 is indeterminate.
Hence A
Good Problem !!
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Mr outreach N Schumi
i know
J^J = J^0 implies J=0.
when we resubstitute, 0^0 is indeterminate.
AND
option 2
J^J = 1
=>j=+1 or -1
insufficient # wch is wrong ofcourse
BUT consider this thing
J^J = 1 ONLY TRUE In case of when J=1
when u put J=-1 then it become (-1)^(-1) IS NOT EQUAL TO 1 (BECAUSE THIS IS NOT LIKE (-1)(-1) )SO WE CAN NOT CONSIDER THIS SCENARIO EQUAL TO ONE...
HENCE ANS IS D
N outreach
wen u put yr ans then put IMO not OA....
ta
HENCE WE CAN SAY THAT
i know
J^J = J^0 implies J=0.
when we resubstitute, 0^0 is indeterminate.
AND
option 2
J^J = 1
=>j=+1 or -1
insufficient # wch is wrong ofcourse
BUT consider this thing
J^J = 1 ONLY TRUE In case of when J=1
when u put J=-1 then it become (-1)^(-1) IS NOT EQUAL TO 1 (BECAUSE THIS IS NOT LIKE (-1)(-1) )SO WE CAN NOT CONSIDER THIS SCENARIO EQUAL TO ONE...
HENCE ANS IS D
N outreach
wen u put yr ans then put IMO not OA....
ta
HENCE WE CAN SAY THAT
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Agree with Ans D
J^J =1
For second statement concider 1 values for J=1 and J=-1
When J=1
1^1 =1
when J=-1
it will be (-1)^ -1 = 1/(-1) =-1 this is not true.
so we can conclude the 2nd statement itself is sufficient.
J^J =1
For second statement concider 1 values for J=1 and J=-1
When J=1
1^1 =1
when J=-1
it will be (-1)^ -1 = 1/(-1) =-1 this is not true.
so we can conclude the 2nd statement itself is sufficient.