Is AD > BC?
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Your Answer
A
B
C
D
E
Global Stats
(1) CD = AB
(2) Angle CAB = Angle BCA
OA A
Source: e-GMAT
Timer
00:00
Your Answer
A
B
C
D
E
Global Stats
Given:
Angles,
ADC = 90\({^0}\)
ABC = 90\({^0}\)
To find:
AD > BC ?
1) CD=AB
Therefore, it becomes a rectangle => AD = BC
SUFFICIENT
2) Angle, CAB = BCA
=> Triangle ABC is 45-90-45
=> \(AC\ =\sqrt{2}BC\ =\ \sqrt{2}\ AB\)
=> AD < \(\sqrt{BC}\)
but can't say AD < BC or not clearly
NOT SUFFICIENT
Choice: A
Angles,
ADC = 90\({^0}\)
ABC = 90\({^0}\)
To find:
AD > BC ?
1) CD=AB
Therefore, it becomes a rectangle => AD = BC
SUFFICIENT
2) Angle, CAB = BCA
=> Triangle ABC is 45-90-45
=> \(AC\ =\sqrt{2}BC\ =\ \sqrt{2}\ AB\)
=> AD < \(\sqrt{BC}\)
but can't say AD < BC or not clearly
NOT SUFFICIENT
Choice: A