John has s pairs of shoes, which is 1/3 as many as Shiela

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John has s pairs of shoes, which is 1/3 as many as Shiela and twice as many as James. In terms of s, how many pairs of shoes do the three of them have combined?

A. 7/3*s
B. 10/3*s
C. 7/2*s
D. 4s
E. 9/2*s

OA E

Source: Princeton Review

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by Scott@TargetTestPrep » Sun Mar 24, 2019 5:16 pm
BTGmoderatorDC wrote:John has s pairs of shoes, which is 1/3 as many as Shiela and twice as many as James. In terms of s, how many pairs of shoes do the three of them have combined?

A. 7/3*s
B. 10/3*s
C. 7/2*s
D. 4s
E. 9/2*s

OA E

Source: Princeton Review

We see that the number of pairs of shoes Sheila has is 3s, and the the number of pair of shoes James has is s/2, thus in total they have:

s + 3s + s/2 = 2s/2 + 6s/2 + s/2 = 9s/2

Answer: E

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