BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

A circle with a radius of 4 feet is cut

Expert replies
by rsarashi » Fri Jun 02, 2017 9:12 am
A circle with a radius of 4 feet is cut from a piece of sheet metal with uniform thickness. The circle weighs 20 pounds. If another circle is cut from the same sheet and weighs 60 pounds, then its radius is closest to which of the following?


A) 6 feet

B) 7 feet

C) 8 feet

D) 9 feet

D) 10 feet

OAB

Please explain.
Join the discussion
Source: — Problem Solving |

by DavidG@VeritasPrep » Fri Jun 02, 2017 9:29 am
rsarashi wrote:A circle with a radius of 4 feet is cut from a piece of sheet metal with uniform thickness. The circle weighs 20 pounds. If another circle is cut from the same sheet and weighs 60 pounds, then its radius is closest to which of the following?


A) 6 feet

B) 7 feet

C) 8 feet

D) 9 feet

D) 10 feet

OAB

Please explain.
If the second circle is three times the weight of the first (60/20), then it stands to reason that the area of the second circle will be three times the area of the first.

Area of circle with radius 4 = 16 *Pi
Area of second circle that is three times the first = 16Pi * 3 = 48Pi
The radius of a circle with an area 48 * Pi is about 7. (The area of a circle with a radius of 7 is 49Pi.) The answer is B
Veritas Prep | GMAT Instructor

Veritas Prep Reviews
Save $100 off any live Veritas Prep GMAT Course
Join the discussion

by [email protected] » Fri Jun 02, 2017 10:14 am
Hi rsarashi,

This question can be approached in a couple of different ways. Here's how we can solve it by TESTing THE ANSWERS.

We're told that a circle , with a radius of 4 feet, cut from a uniform piece of sheet metal would weigh 20 pounds. Thus, we can equate area with weight...

A = (pi)(R^2) = (pi)(4^2) = 16pi ft^2 = 20 pounds

Thus, every 16pi ft^2 equates to 20 pounds. We're asked to find the approximate radius of a circle that would weight 60 pounds (which is triple the weight of this circle). Thus, we're looking for an area that is approximately triple this area. Let's TEST Answer B...

Answer B: 7 feet

With a radius of 7 feet, this circle would have an area of...
A = (pi)(R^2) = (pi)(7^2) = 49pi = a little more than triple the area of the other circle. While you can TEST Answers A and C if you like, you'll find that Answer B is closest.

Final Answer: B

GMAT assassins aren't born, they're made,
Rich
Contact Rich at [email protected]
Image
Join the discussion

by Jay@ManhattanReview » Sat Jun 03, 2017 11:19 pm
rsarashi wrote:A circle with a radius of 4 feet is cut from a piece of sheet metal with uniform thickness. The circle weighs 20 pounds. If another circle is cut from the same sheet and weighs 60 pounds, then its radius is closest to which of the following?


A) 6 feet

B) 7 feet

C) 8 feet

D) 9 feet

D) 10 feet

OAB

Please explain.
Weight of a circular disk = Volume of a circular disk * density of metal = Area of the disk * Thickness of the disk * Density of metal

Since the circular disc is cut from the same metal sheet with a uniform piece, Thickness of the disk and Density of metal are constant

Thus, Weight of a circular disk is proportional to Area of the disk

Weight of a circular disk with 4 feet radius / Weight of a circular disk with x feet radius = Area of the disk with 4 feet radius / Area of the disk with x feet radius

=> 20/60 = π*4^2 / π*x^2
=> 1/3 = 16/x^2
=> x = √48 = ~7 feet

The correct answer: B

Hope this helps!

-Jay
_________________
Manhattan Review GMAT Prep

Locations: New York | Barcelona | Manila | Melbourne | and many more...

Schedule your free consultation with an experienced GMAT Prep Advisor! Click here.
Join the discussion

rsarashi wrote: ↑
Fri Jun 02, 2017 9:12 am
A circle with a radius of 4 feet is cut from a piece of sheet metal with uniform thickness. The circle weighs 20 pounds. If another circle is cut from the same sheet and weighs 60 pounds, then its radius is closest to which of the following?


A) 6 feet

B) 7 feet

C) 8 feet

D) 9 feet

D) 10 feet

OAB

Please explain.
The area of the circle of radius 4 feet is 16π. Let r = the radius of the circle that weighs 60 pounds. Thus, the area of such a circle is πr^2. Since the weight of the circle is proportional to its area, we have:

16π / 20 = πr^2 / 60

Multiplying the equation by 60, we obtain:

48π = πr^2

r^2 = 48

r ≈ 7

Answer: B

Scott Woodbury-Stewart
Founder and CEO
[email protected]

Image

See why Target Test Prep is rated 5 out of 5 stars on BEAT the GMAT. Read our reviews

ImageImage
Join the discussion