If x is an integer, is y an integer?
(1) The average (arithmetic mean) of
x, y and y - 2 is x.
(2) The average (arithmetic mean) of
x and y is not an integer.
OA is A
y an integer?
This topic has expert replies
- vk_vinayak
- Legendary Member
- Posts: 502
- Joined: Tue Jun 03, 2008 11:36 pm
- Thanked: 99 times
- Followed by:21 members
Option 1. => y-2, x, y are three consecutive integers. SUFgrandh01 wrote:If x is an integer, is y an integer?
(1) The average (arithmetic mean) of
x, y and y - 2 is x.
(2) The average (arithmetic mean) of
x and y is not an integer.
OA is A
Option 2. => Ix x=2 and y=3, then average in not an integer. If x=2 and y=2.5 then also average is not an integer. INSUF.
Ans A.
- VK
I will (Learn. Recognize. Apply)
I will (Learn. Recognize. Apply)
- cypherskull
- Senior | Next Rank: 100 Posts
- Posts: 94
- Joined: Sat Mar 31, 2012 3:39 am
- Location: Calcutta
- Thanked: 8 times
Given x is an interger
From Statement (1)
[x + y + (y-2)]/3 = x
=> x + 2y - 2 = 3x
=> 2y - 2 = 2x
=> y - 1 = x
=> y = x + 1 => Since x is an integer, x + 1 (=y) will also be an integer [Sufficient]
From statement (2)
(x + y)/2 => not an integer. Here y can take on both integer as well as non-integer values.
[Not sufficient]
[spoiler]Ans: A[/spoiler]
From Statement (1)
[x + y + (y-2)]/3 = x
=> x + 2y - 2 = 3x
=> 2y - 2 = 2x
=> y - 1 = x
=> y = x + 1 => Since x is an integer, x + 1 (=y) will also be an integer [Sufficient]
From statement (2)
(x + y)/2 => not an integer. Here y can take on both integer as well as non-integer values.
[Not sufficient]
[spoiler]Ans: A[/spoiler]
Regards,
Sunit
________________________________
Kill all my demons..And my angels might die too!
Sunit
________________________________
Kill all my demons..And my angels might die too!