If \(x\) is positive, then \(\dfrac1{\sqrt{x+1}+\sqrt{x}}=\)

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If \(x\) is positive, then \(\dfrac1{\sqrt{x+1}+\sqrt{x}}=\)

A) \(1\)

B) \(x\)

C) \(\dfrac1{x}\)

D) \(\sqrt{x+1}-\sqrt{x}\)

E) \(\sqrt{x+1}+\sqrt{x}\)

Answer: D

Source: Veritas Prep