Source: Princeton Review
There are 8 job applicants sitting in a waiting room, 4 women and 4 men. If 2 of the applicants are selected at random, what is the probability that both will be women?
A. \(\dfrac{1}{4}\)
B. \(\dfrac{3}{7}\)
C. \(\dfrac{5}{2}\)
D. \(\dfrac{3}{14}\)
E. \(\dfrac{1}{10}\)
The OA is D
There are 8 job applicants sitting in a waiting room, 4 women and 4 men. If 2 of the applicants are selected at random,
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P(both selected people are women) = P(1st selection is a woman AND 2nd selection is a woman)BTGmoderatorLU wrote: ↑Wed Sep 15, 2021 8:04 amSource: Princeton Review
There are 8 job applicants sitting in a waiting room, 4 women and 4 men. If 2 of the applicants are selected at random, what is the probability that both will be women?
A. \(\dfrac{1}{4}\)
B. \(\dfrac{3}{7}\)
C. \(\dfrac{5}{2}\)
D. \(\dfrac{3}{14}\)
E. \(\dfrac{1}{10}\)
The OA is D
= P(1st selection is a woman) x P(2nd selection is a woman)
= 4/8 x 3/7
= 3/14
Answer: D
Aside:
P(1st selection is a woman) = 4/8, since there are 8 people, and 4 of them are women
P(2nd selection is a woman) = 3/7. Once we have selected a woman for the 1st selection, there are 7 people remaining, and 3 of them are women
Cheers,
Brent