Can someone help me determine why selection (1) is sufficient? When I'm doing the problem I believe x could be three, making y = 0 so it would actually be insufficient?
If x is an integer, is y an integer?
(1) (4x + 4y)/2 = 6
(2) (3x + 6y)/3 = 5
In selection (1), you can simplify the expression to be x + y = 3. If this is the case, x can be 1, 2, or 3 since x must be an integer. BUT, this makes y either 0, 1, or 2. Since y can be 0, statement (1) is insufficient, correct? The service I'm using said I was wrong and statement (1) is sufficient.
Would appreciate any input.
Thanks
If x is an integer, is y an integer?
(1) (4x + 4y)/2 = 6
(2) (3x + 6y)/3 = 5
In selection (1), you can simplify the expression to be x + y = 3. If this is the case, x can be 1, 2, or 3 since x must be an integer. BUT, this makes y either 0, 1, or 2. Since y can be 0, statement (1) is insufficient, correct? The service I'm using said I was wrong and statement (1) is sufficient.
Would appreciate any input.
Thanks














