If the letters of the word A, F, T, E, R are permuted and arranged in a dictionary form like after, then for some (n > 2) how many other possible ways are there?
A. 119
B. 117
C. 88
Source is TestMagic. I dont have the OA
How to solve this?
This topic has expert replies
-
- Senior | Next Rank: 100 Posts
- Posts: 49
- Joined: Mon Apr 28, 2008 5:33 am
- Thanked: 2 times
-
- Senior | Next Rank: 100 Posts
- Posts: 49
- Joined: Mon Apr 28, 2008 5:33 am
- Thanked: 2 times
I thought that they are asking for the number of all possible words that could appear after the word "AFTER" in the dictionary using letters A,F,T,E,R. The word should atleast be more than 2 characters in length. Let me know if this helps.
-
- Senior | Next Rank: 100 Posts
- Posts: 49
- Joined: Mon Apr 28, 2008 5:33 am
- Thanked: 2 times
This question is poorly constructed so I'm struggling to give you a proper answer.
As has already been said, you have 119 x 5 letter combinations (discounting AFTER)
You have 5C4 * 4! 4 letter combinations (120)
You have 5C3 * 3! 3 letter combinations (60)
You have 5C2 * 2! 2 letter combinations (20)
= 119 + 120 + 60 + 20 = 319
I think you need to confirm the question wording
As has already been said, you have 119 x 5 letter combinations (discounting AFTER)
You have 5C4 * 4! 4 letter combinations (120)
You have 5C3 * 3! 3 letter combinations (60)
You have 5C2 * 2! 2 letter combinations (20)
= 119 + 120 + 60 + 20 = 319
I think you need to confirm the question wording
Assuming n>2 meaning words with more than 2 alphabets need to be formed
Choosing 3: 5C3 * 3! = 60
Choosing 4: 5C4 * 4! = 120
Choosing 5 5C5 * 5! - 1(AFTER) = 119
Total = 60+120+119 = 299
I am not sure if i am right or not!!
Choosing 3: 5C3 * 3! = 60
Choosing 4: 5C4 * 4! = 120
Choosing 5 5C5 * 5! - 1(AFTER) = 119
Total = 60+120+119 = 299
I am not sure if i am right or not!!