If k is an odd integer, which of the following must be an even integer?
A k2 − 4
B 3k + 2
C 2k + 1
D (12k)/8
E (6k)/3
You can solve by substituting an even number, 0, into each of the options. Only C gives an even result hence C is the right answer.
If k is an odd integer, which of the following must be an even integer?
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Solution:GMATprofessional21 wrote: ↑Wed Aug 05, 2020 2:13 amIf k is an odd integer, which of the following must be an even integer?
A k2 − 4
B 3k + 2
C 2k + 1
D (12k)/8
E (6k)/3
Since 6k/3 = 2k and 2k is a multiple of 2, then it must be even.
Answer: E
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