With both valves open, the pool will be filled with water in 48 minutes. The first valve alone would fill the pool in 2 hours. What is the capacity of the pool if every minute the second valve admits 50 cubic meters of water more than the first?
9000 cubic meters
10500 cubic meters
11750 cubic meters
12000 cubic meters
12500 cubic meters
:roll:
With both valves open
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- gmat740
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Hey you need to do a small correction. I hope I am correct,because that is the only way I figured out this question can be solved.
IMO 12000
A(1st valve) can fill in 2 hrs
together = 48 mints =4/5 hrs
1/a + 1/b = 5/4
1/2 +1/b = 5/4
b= 4 hrs
b= second valve
Now its given
every minute the first valve admits 50 cubic meters of water more than the second
Since A can fill in 2 hrs,so definitely speed of A is higher than that of B
If B has speed of V
Speed of A =2V
Now look at what's the condition
2v = v+50
v= 50
capacity of pool = speed of B* time taken by B
= 50*4hrs*60(speed is given per minute)
=12000
Hope this helps
I think this would be reverse : if every minute the first valve admits 50 cubic meters of water more than the second?What is the capacity of the pool if every minute the second valve admits 50 cubic meters of water more than the first?
IMO 12000
A(1st valve) can fill in 2 hrs
together = 48 mints =4/5 hrs
1/a + 1/b = 5/4
1/2 +1/b = 5/4
b= 4 hrs
b= second valve
Now its given
every minute the first valve admits 50 cubic meters of water more than the second
Since A can fill in 2 hrs,so definitely speed of A is higher than that of B
If B has speed of V
Speed of A =2V
Now look at what's the condition
2v = v+50
v= 50
capacity of pool = speed of B* time taken by B
= 50*4hrs*60(speed is given per minute)
=12000
Hope this helps